The size of the force varies inversely as the square of the distance between the two charges. Therefore, if the distance between the two charges is doubled, the attraction or repulsion becomes weaker, decreasing to one-fourth of the original value.
Answer:
The ball's initial kinetic energy
The ball comes to a stop at B. At this point its initial kinetic energy is converted into potential energy
Explanation:
A ball is fixed to the end of a string, which is attached to the ceiling at point P. As the drawing shows, the ball is projected downward at A with the launch speed v0. Traveling on a circular path, the ball comes to a halt at point B. What enables the ball to reach point B, which is above point A? Ignore friction and air resistance.
From conservation of energy which states that energy can neither be created nor be destroyed, but can be transformed from one form to another.
Ki+Ui=Kf+Uf
Ki=initial kinetic energy
Ui=initial potential energy
Kf=final kinetic energy
Uf=final potential energy
we know that 
m=mass of the ball
ha=downward height a
hb=upward height b
u=initial velocity u
v=final velocity v, which is 0
g=acceleration due to gravity
v=0 at final velocity
1/2mu^2+mgha=0+1/2mv^2
ha=hb+Ki/mh
From the above equation, we can conclude that the ball's initial kinetic energy is responsible for making the ball reach point B.
Point B is higher than point A from the motion gained by the ball
Incomplete question as we have not told to find what.So the complete question is here
A vessel at rest at the origin of an xy coordinate system explodes into three pieces. Just after the explosion, one piece, of mass m, moves with velocity (-60 m/s)i and a second piece, also of mass m, moves with velocity (-60 m/s)j. The third piece has mass 3m.Just after the explosion, what are the (a) magnitude and (b) direction of the velocity of the third piece?
Answer:

Explanation:
Given data
The vessel at rest
Piece one,of mass m,moves with velocity=(-60 m/s)i
Piece two,of mass m,moves with velocity=(-60 m/s)j
Piece three,of mass 3m
As the linear momentum is conserved in this system,Because the system is closed and no external force acting on it
So momentum is given as

As the vessel at rest so the initial momentum is zero
So

Answer:
a).p=15.67kg*m/s
b). F=7.83N
Explanation:
change in momentum is the subtraction from "after momentum" of the "before momentum" as momentum is a vector quantity this is a vector subtraction.
initial momentum of ball
m1v1 = (0.145)(44.0) = 6.38 kg-m/s
after momentum
m1v2 = (0.145)(64.0) = 9.28 kg-m/s
since these momentums are 180° opposite one must be called negative so their difference
6.38+9.28= 15.67 kg-m/s
change in momentum = 15.67 kg-m/s ANS a1
Impulse = change in momenutm = 15.67 ANS a2
b)
Impulse =Favg*t
I=(2.00)Favg
Impulse from (a2) = 15.67
Favg = 15.67/2.00 =
F= 7.83 N
The atomic mass. By taking two different types of the same element and calculating the average based on the amount of each type in the world, you get the basic atomic difference.