Answer:
i = 0.5 A
Explanation:
As we know that magnetic flux is given as
![\phi = NBA](https://tex.z-dn.net/?f=%5Cphi%20%3D%20NBA)
here we know that
N = number of turns
B = magnetic field
A = area of the loop
now we know that rate of change in magnetic flux will induce EMF in the coil
so we have
![EMF = NA\frac{dB}{dt}](https://tex.z-dn.net/?f=EMF%20%3D%20NA%5Cfrac%7BdB%7D%7Bdt%7D)
now plug in all values to find induced EMF
![EMF = (20)(50 \times 10^{-4})(\frac{6 - 2}{2})](https://tex.z-dn.net/?f=EMF%20%3D%20%2820%29%2850%20%5Ctimes%2010%5E%7B-4%7D%29%28%5Cfrac%7B6%20-%202%7D%7B2%7D%29)
![EMF = 0.2 volts](https://tex.z-dn.net/?f=EMF%20%3D%200.2%20volts)
now by ohm's law we have
![current = \frac{EMF}{Resistance}](https://tex.z-dn.net/?f=current%20%3D%20%5Cfrac%7BEMF%7D%7BResistance%7D)
![i = \frac{0.2}{0.40} = 0.5 A](https://tex.z-dn.net/?f=i%20%3D%20%5Cfrac%7B0.2%7D%7B0.40%7D%20%3D%200.5%20A)
Since the y axis stayed consistent, we can assume it did not move at all.
(So your answer would be A)
All will have a dominant trait I can't see the following statments
Answer:
9758 how many significant figures
Answer:
Explanation:
All the displacement will be converted into vector, considering east as x axis and north as y axis.
5.3 km north
D = 5.3 j
8.3 km at 50 degree north of east
D₁= 8.3 cos 50 i + 8.3 sin 50 j.
= 5.33 i + 6.36 j
Let D₂ be the displacement which when added to D₁ gives the required displacement D
D₁ + D₂ = D
5.33 i + 6.36 j + D₂ = 5.3 j
D₂ = 5.3 j - 5.33i - 6.36j
= - 5.33i - 1.06 j
magnitude of D₂
D₂²= 5.33² + 1.06²
D₂ = 5.43 km
Angle θ
Tanθ = 1.06 / 5.33
= 0.1988
θ =11.25 ° south of due west.