A and D are complementary
B and C are supplementary
Complementary angles are 90 degrees 59+31=90
Supplementary angles are 180 degrees 119+61=180
In the figure, ABCD is a trapezoid with legs AB and CD.
Join AC and BD.
For the triangle CAD, from the vertex C, draw an altitude CE and for the triangle ABD, from the vertex B, draw an altitude BF.
Clearly, CE = BF = h (say) --- (1)
Note that the base of the triangles CAD and ABD are the same and is AD.
It is given that ar(CAD) = 
.
Now, ar(ABD) = 
= 
from (1)
= ar(CAD)
= .
Hence, area of Δ ABD = ..
Ths is easier than it looks.
115 - - 15 = 115 + 15 = 130 degrees difference.
Answer:
60 degrees.
Step-by-step explanation:
Since you know that y = 74 because they are vertical angles, and 46 = the angle across from it (there is a theorem for it). Since one line is 180 degrees, and you already know the two sides next to x, which is 74 and 46, you can do 180 - 74 - 46. Your final answer should be 60 degrees.
Answer:
82° because
98° + 70° = 168°
360° - 168° = 192°
192° is for two angles, so it can't be 192°, 220°
it's not VERY obtuse angle. So it remains only 82°
