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solmaris [256]
3 years ago
11

How to convert 250 in scientific notation

Chemistry
1 answer:
cricket20 [7]3 years ago
4 0
In scientific notation, a number is less than ten but more than one.

Move the decimal point from 0, 250.000 <- this is the same as 250 to between 2 and 5.

I had to move two spaces.

2.5^2

I hope this helps!
~kaikers
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An octet is equal to
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The answer will be 8.

Edit:

Sorry! I was wrong earlier.

An octet is when there is 8 electrons in the valence shell.

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3 0
3 years ago
1
Delvig [45]

Answer:

The molarity of the solution is 0,99M

Explanation:

We calculate the weight of 1 mol of NaCl from the atomic weights of each element of the periodic table. Then, we calculate the molarity, which is a concentration measure that indicates the moles of solute (in this case NaCl) in 1000ml of solution (1 liter)

Weight 1 mol NaCl= Weight Na + Weight Cl= 23 g + 35, 5 g= 58, 5 g

58, 5 g-----1 mol NaCl

145 g ---------x= (145 g x 1 mol NaCl)/58, 5 g= 2,48 mol NaCl

2,5 L solution------ 2, 48 mol NaCl

1 L solution------x= (1 L solutionx 2, 48 mol NaCl)/2,5L solution

x=0,99 mol NaCl---> The solution is 0,99 molar (0,99 M)

Read more on Brainly.com - brainly.com/question/15453053#readmore

6 0
4 years ago
Why does glutton free bread mold faster
Ann [662]
The reason is it has more sugar and energy to feed fungi, causing it to mold.
5 0
3 years ago
Read 2 more answers
Convert 1.71 × 1024 atoms of carbon to moles of carbon.
beks73 [17]
You need to use Avogadro's constant to convert from atoms of carbon to moles of carbon.

1.71*10^24 atoms C * (1 mole/6.022*10^23 atoms) = 2.84 moles of carbon
7 0
4 years ago
An air tight freezer measures 4 mx 5 m x 2.5 m high. With the door open, it fills with 22 °C air at 1 atm pressure.
____ [38]

Answer:

(a) Density of the air = 1.204 kg/m3

(b) Pressure = 93772 Pa or 0.703 mmHg

(c) Force needed to open the door =  15106 N

Explanation:

(a) The density of the air at 22 deg C and 1 atm can be calculated using the Ideal Gas Law:

\rho_{air}=\frac{P}{R*T}

First, we change the units of P to Pa and T to deg K:

P=1 atm * \frac{101,325Pa}{1atm}=101,325 Pa\\\\ T=22+273.15=293.15^{\circ}K

Then we have

\rho_{air}=\frac{P}{R*T}=\frac{101325Pa}{287.05 J/(kg*K)*293.15K} =1.204 \frac{kg}{m3}

(b) To calculate the change in pressure, we use again the Ideal Gas law, expressed in another way:

PV=nRT\\P/T=nR/V=constant\Rightarrow P_{1}/T_{1}=P_{2}/T_{2}\\\\P_{2}=P_{1}*\frac{T_{2}}{T_{1}}=101325Pa*\frac{7+273.15}{22+273.15}=101,325Pa*0.9254=93,772Pa\\\\P2=93,772 Pa*\frac{1mmHg}{133,322Pa}= 0.703 mmHg

(c) To calculate the force needed to open we have to multiply the difference of pressure between the inside of the freezer and the outside and the surface of the door. We also take into account that Pa = N/m2.

F=S_{door}*\Delta P=2m^{2} *(101325Pa - 93772Pa)=2m^{2} *7553N/m2=15106N

7 0
3 years ago
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