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castortr0y [4]
4 years ago
14

Propose structures that meet the following descriptions. Use bond-line notation to draw your structural formulas. a. ketone with

five carbons and one alcohol c. alkane (no double bonds) with the formula, C6H12 e. nitrile with the formula, C5H9N g. phenol with a carboxylic acid group adjacent to hydroxyl i. amide with the formula, C3H7NO k. a secondary thiol with 3 carbons m. a primary alcohol with five carbons b. a-ketoester (i.e., a molecule with a ketone one carbon away from an ester) d. dialdehyde with the formula, C4H6O2 f. b-ketocarboxylic acid (i.e. a molecule with a ketone two carbons away from a carboxylic acid) h. amino acid (i.e. a carbon atom attached to both a carboxylic acid and an amine j. ether with the formula, C4H10O l. alkane with five carbons, one of which is a quaternary carbon n. hydroxy aldehyde (a compound containing an aldehyde and hydroxy group)

Chemistry
1 answer:
bija089 [108]4 years ago
7 0

Answer:

See explanation

Explanation:

In putting up prospective structures for the compounds, we must consider the tetra valency of carbon. Again you must read the description carefully before drawing each structure.

In each of the proposed structures, the number of atoms present must reflect the condensed structural formula given in the question.

Proposed structures for each chemical specie in the question are shown in the images attached.

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Answer:

C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

Explanation:

La ley de conservación de la materia implica que en una reacción química los átomos en los reactivos son iguales a la cantidad de átomos en los productos:

A C2H5OH(l) + O2(g) → CO2 + H2O

En los reactivos hay dos átomos de carbono pero en los productos solo 1. De esta manera, no cumple la ley de conservación.

B C2H5OH(l) + O2(g) → 2CO2 + H2O

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C C2H5OH(l) + 3O2(g) → 2CO2 + 3H2O

En los reactivos y productos hay: 2 átomos de carbono, 6 átomos de hidrógeno y 7 átomos de oxígeno. Cumple la ley de conservación.

D C2H5OH(l) + O2(g) → 2CO2 + 3H2O

En los reactivos hay 3 átomos de oxígeno y en los productos 7. No cumple la ley de conservación.

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6 0
3 years ago
Using the formula M1V1 = M2V2 , how many milliliters of a 2.50 M hydrochloric acid solution is required to make 100.0 mL of a 0.
olga nikolaevna [1]

30ml of a 2.50 M hydrochloric acid solution is required to make 100.0 mL of a 0.750 M solution.

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HCl is an acid which is made up of hydrogen and chlorine gas.

By the formula of dilution

M1V1 = M2V2

where V1 = 2.50 m

M2 = 100.0

V2 = 0.750 m

M1 × 2.50 m = 100.0 × 0.750 m

M1 = 30 ml

Thus, the M1 is 30 ml option a is correct.

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brainly.com/question/3637432

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