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3 years ago

An aircraft is flying at a speed of 255 knots.How fast it is in meter per second

Physics

2 answers:

motikmotik3 years ago

8 0

131.1833332234 meters per second.

patriot [66]3 years ago

7 0

The answer is 131.1833332234 Meters per second. ;)

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In a warehouse, the workers sometimes slide boxes along the floor to move them. Two boxes were sliding toward each other and cra

san4es73 [151]

Answer:

Box 1 has more mass than box 2.

Explanation:

Box 1 has more mass than box 2, as it caused a greater affect in the change of speed of box 2. During a collision, the object with a lesser mass will be affected more, causing the velocity to change more. Because box one is greater than box 2, it caused a larger change in speed when they collided.

3 0

3 years ago

A transverse, wave travelling on a chord is represented by D=0.22sin (5.6x+34t) where D and x are inmeters and t is in seconds.

ArbitrLikvidat [17]

Answer:

a) λ = 1.12 m

b) f = 5.41 Hz

c) v = 154.54 m/s

d) A = 0.22m

$v_D_{max}=7.48\frac{m}{s}\\\\v_D_{min}=-7.48\frac{m}{s}\\\\$

Explanation:

You have the following equation for a wave traveling on a cord:

$D=0.22sin(5.6x+34t)$ (1)

The general expression for a wave is given by:

$D=Asin(kx-\omega t)$ (2)

By comparing the equation (1) and (2) you have:

A: amplitude of the wave = 0.22m

k: wave number = 5.6 m^-1

w: angular velocity = 34 rad/s

a) The wavelength is given by substitution in the following expression:

$\lambda=\frac{2\pi}{k}=\frac{2\pi}{5.6m^{-1}}=1.12m$

b) The frequency is:

$f=\frac{\omega}{2\pi}=\frac{34s^{-1}}{2\pi}=5.41Hz$

c) The velocity of the wave is:

$v=\frac{\omega}{k}=\frac{34s^{-1}}{0.22m^{-1}}=154.54\frac{m}{s}$

d) The amplitude is 0.22m

e) To calculate the maximum and minimum speed of the particles you obtain the derivative of the equation of the wave, in time:

$v_D=\frac{dD}{dt}=(0.22)(34)cos(5.6x+34t)\\\\v_D=7.48cos(5.6x+34t)$

cos function has a minimum value -1 and maximum +1. Then, you obtain for maximum and minimum velocity:

$v_D_{max}=7.48\frac{m}{s}\\\\v_D_{min}=-7.48\frac{m}{s}\\\\$

6 0

3 years ago

8. Find the momentum of a photon in eV/c and in Kg. m/s if the wavelength is (a) 400nm ; (b) 1 Å = 0.1 nm, (c) 3 cm ; and (d) 2

nataly862011 [7]

We use the formula: p = E/c where E = hc / λ. hence, p = h/ λ. where h is the Planck's constant: 6.62607004 × 10-34 m2 kg / s and <span>λ is the wavelenght.
</span>
a) p = <span>6.62607004 × 10-34 m2 kg / s / 0.1 x10^-9 m = 6.62607 x 10-24 m kg/s
</span>b) p = 6.62607004 × 10-34 m2 kg / s / 3 x10^-2 m = 2.20869 <span>x 10-32 m kg/s
</span>b) p = 6.62607004 × 10-34 m2 kg / s / 2 x10^-9 m = 3.3130 <span>x 10-25 m kg/s</span>

7 0

3 years ago

You are approaching a police car at 68. 1 mph and the police car is approaching you at 94. 8 mph. Assume that the speed of sound

Veronika [31]

We will hear the sound of siren of frequency 1553.4606 Hz.

<h3>What is Doppler Effect?</h3>

The apparent change in wave frequency brought on by the movement of a wave source is known as the Doppler effect. When the wave source is coming closer and when it is moving away, the perceived frequency changes. The Doppler effect explains why we hear a passing siren's sound changing in pitch.

according to Dopplers Effect,

$f'=[\frac{v + v_{0} }{v - v_{s} } ]f$