Answer:
<h2>
f₀ = 158.12 Hertz</h2>
Explanation:
The fundamental frequency of the string f₀ is expressed as f₀ = V/4L where V is the speed experienced by the string.
where T is the tension in the string and
is the density of the string
Given T = 600N and
= 0.015 g/cm = 0.0015kg/m

The next is to get the length L of the string. Since the string is stretched and fixed at both ends, 200 cm apart, then the length of the string in metres is 2m.
L = 2m
Substituting the derived values into the formula f₀ = V/2L
f₀ = 632.46/2(2)
f₀ = 632.46/4
f₀ = 158.12 Hertz
Hence the fundamental frequency of the string is 158.12 Hertz
The pitch of a sound come from the frequency of the soundwave, soundwaves that have bigger frequencies sound with a high pitch and soundwaves with less frequencie have low pitch.
Answer:
option A is correct as 1 yard consist of 0.9144 meter which is less than one meter
Explanation:
from the above given statement option 1 is true
1 yard is equal to 0.9144 meter
while
1 mile is equal to 1.60934 km
1 foot is equal to 30.48 centimeter
1 inch is equal to 2.54 centimeter
therefore all these units [left one] are larger than their respective conversion [ right one unit]
therefore option A is correct as 1 yard consist of 0.9144 meter which is less than one meter