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3 years ago

I feel dvmb for asking this question but... help? Please?

Physics

1 answer:

VMariaS [17]3 years ago

8 0

Force, it can speed up or slow down an object which can change the direction in which an object is moving.

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Steam enters an adiabatic turbine at 5 MPa and 4500C and leaves at a pressure of 1.4 MPa. Determine the work output of the turbi

REY [17]

Answer:350.92 KJ/kg

Explanation:

Given the process is reversible adiabatic i.e it is isentropic

$P_1=5 MPa$

$T_1=4500 MPa$

$P_2=1.4 MPa$

From steam table

$h_1=3317.03KJ/kg$

For isentropic process $s_1=s_2$

at $P_2=1.4 MPa$

$s_2=6.82 KJ/kg-k$

$h_2=2966.11 KJ/kg$

Therefore Work output of the turbine per unit mass of steam is = $h_1-h_2$

=3317.03-2966.11

=350.92 KJ/kg

8 0

3 years ago

Liquid water at 120 kPa enters a 7-kW pump where its pressure is raised to 5.6 MPa. If the elevation difference between the exit

ziro4ka [17]

Answer:

The answer is given below

Explanation:

Things provided in the statement:

Pressure P1 = 120 kPa and P2 = 5.6 MP or 5600 kPa

Power, W = 7 kW

Elevation difference = ∆z = 10 m

Mass of flow = m˙

So potential energy changes may be significant

Specific volume of water V= 0.001 m³/kg

Now putting the values in the formula

Power, W = m˙ x V (P1 - P2) + m˙ x g x ∆z

7 = m˙ x 0.001 (5600 - 120 ) + m˙ x 9.8 x 10 x (1 kJ/kg/ 1000 m^2/s^2)

7 = m˙ x 5.48 + m˙ x 0.098

7 = m ˙x 5.38

m˙ = 7/5.38

So mass flow m˙ = 1.301 kJ/s

8 0

3 years ago

A circular loop of wire having a radius of 5.58 cm carries a current of 0.230 A. A vector of unit length and parallel to the dip

Sidana [21]

Answer:

see explanation

Explanation:

Given quantities:

radius = r = 0.0558 [m]

current = I = 0.23 [A]

$\vec{B} =$

Now we solve this by obtaining the torque acting on the dipole

$\tau = M \times B$

We obtain the magnetic moment vector M, first, |M| is defined as $M = IA$ , where A is the cross-section area of the loop which is $A = \pi r^2=\pi (0.0558)^2= 0.00978 [m^2]$ then

$|M| = 0.23*0.00978 = 0.00225 [A/m^2]$

now the magnetic moment vector is equal to the magnetic dipole moment vector multiplied the magnitude we just obtained $\vec{M} = M \hat M$

$= 0.00225 *$

Now:

a ) $\tau = M \times B$

b) $U = -M \cdot B$

a) the determinant gives us:

b) the dot product gives = $-1*-7.2*10^{-6} = 7.2*10^{-6}[J]$

6 0

3 years ago

1. Convert the following measurements to the units specified. 2.5 days to seconds

Anvisha [2.4K]

Answer: 216000

Explanation:

60 seconds in 1 hour

24 hours in a day = 1440

148 hours in 7 days

6 0

2 years ago

If a sound wave is produced with a wavelength of 1.04m what is the waves frequency

dmitriy555 [2]

You should just ask the wave

5 0

3 years ago