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Semenov [28]
2 years ago
10

Anyone really good with Organic chemistry

Chemistry
1 answer:
dlinn [17]2 years ago
3 0

Answer:

umm maybe give me you're question I'll try

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Answer : The technology that can make coal a cleaner fuel is to use lower quality of coal with high sulfur content.

Explanation : Using lower quality of coal with high amount of sulfur in it can make coal a cleaner fuel because of high amount of sulfur it will have better combustion.  
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Un gas ocupa un volumen de 12 litros a una presión de 912 mm Hg. Si permanece constante la temperatura, ¿A qué presión el gas oc
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The  pressure occupied is 1, 8 atm.

Explanation:

We use the Boyle´s Mariotte ´s law: for a given mass of gas at constant temperature, the pressure and volume vary inversely proportionally: P1xV1= P2xV2. The unit of pressure is converted to mmHg in atm.

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Terry, a student, performs a titration. He completes these steps as part of his titration procedure: 1. He cleans and rinses a b
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D

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Question 21 of 25
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3 years ago
Determine the empirical formula of the following compound if a sample contains 0.104 molK, 0.052 molC, and 0.156 molO;?
faltersainse [42]

Answer:

K₂CO₃    

Explanation:

Given parameters:

Number of moles of K = 0.104mol

Number of moles of C = 0.052mol

Number of moles of O = 0.156mol

Method

From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.

Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.

  • Divide the given moles through by the smallest which is C, 0.052mol.
  • Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
  • This is the empirical formula

Solution

Elements                             K                       C                    O

Number of moles            0.104                0.052            0.156

Dividing by the

smallest                       0.104/0.052     0.052/0.052  0.156/0.052

                                            2                           1                     3

The empirical formula is K₂CO₃      

3 0
2 years ago
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