Anyone really good with Organic chemistry

The sodium isotope with 13 neutrons. Express your answer as an isotope

wariber [46]

Answer:

$\large\boxed{\large\boxed{^{24}_{11}Na}}$

Explanation:

The question is asking to write the isotopic symbol of the form $^A_ZX$ for the sodium isotope with 13 neutrons.

In general, the isotopic symbol in the given form shows:

The element's chemical symbol: X

A: mass number of the isotope, written as a superscript to the left of the element's simbol, and

A = number of protons + number of neutrons

Z: atomic number of the isotope, written as a subscript to the left of the elements's symbol,

Z = number of protons

The atomic symbol of sodium is Na.

The atomic number, or number of protons, is the same for every isotope of the element, and you can find it in any periodic table. Tha atomic number of sodium is 11. Thus:

Z = 11

The mass number is the number of protons plus neutrons, hence:

A = 11 + 13 = 24

Now you can write the isotope symbol for the sodium isotope with 13 neutrons:

$^{24}_{11}Na$

6 0

3 years ago

Is a push or a pull. A.FORCE B.MASS ???

Alex_Xolod [135]

A.Force because your adding pressure to what you are pushing or pulling.

4 0

3 years ago

Suppose a liquid level from 5.5 to 8.6 m is linearly converted to pneumatic pressure from 3 to 15 psi. What pressure will result

wlad13 [49]

Answer:

a) P = 9.58 psi for h=7.2 m

b) P=4.7 psi for h=5.94 m

Explanation:

Since the pressure Pon a static liquid level h is

P= p₀ + ρ*g*h

where p₀= initial pressure , ρ=density , g = gravity

then he variation of the liquid level Δh will produce a variation of pressure of

ΔP= ρ*g*Δh → ΔP/Δh = ρ*g = ( 15 psi - 3 psi) /( 8.6 m - 5.5 m) = 12/3.1 psi/m

if the liquid level is converted linearly

P = P₁ + ΔP/Δh*(h -h₁)

therefore choosing P₁ = 3 psi and h₁= 5.5 m , for h=7.2 m

P = 3 psi + 12/3.1 psi/m *(7.2 m -5.5 m) = 9.58 psi

then P = 9.58 psi for h=7.2 m

for P=4.7 psi

4.7 psi = 3 psi + 12/3.1 psi/m *(h -5.5 m)

h = (4.7 psi - 3 psi)/ (12/3.1 psi/m) + 5.5 m = 5.94 m

then P=4.7 psi for h=5.94 m

5 0

3 years ago

A patient receives 3.3 L of glucose solution intravenously (IV). If 100. mL of the solution

artcher [175]

Answer:

660kcal

Explanation:

The question is missing the concentration of the glucose solution. Standard glucose concentration for IV solution is 5% or 5g of glucose every 100mL of solution.

We need to determine how many grams of glucose are there inside the solution. The number of glucose in 3.3L solution will be:

3.3L * (1000mL / L) * (5g/100mL)= 165 g.

If glucose will give 4kcal/ g, then the total calories 165g glucose give will be: 165g * 4kcal/ g= 660kcal.

6 0

3 years ago

Arrange the elements in order of increasing ionization energy. Use the

UNO [17]

Answer:

Gallium, Phosphorus, Chlorine, Fluorine

Explanation:

Arrange the elements in order of increasing ionization energy. Use the periodic table to identify their positions on the table.

Drag each tile to the correct box.

Tiles

chlorinefluorinegalliumphosphorus

Sequence

5 0

3 years ago

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