Explanation:
I think 20
0 in the photo should be 1, 1, 1
Hello!
We have the following data:
ps: we apply Ka in benzoic acid to the solution.
[acid] = 0.235 M (mol/L)
[salt] = 0.130 M (mol/L)
pKa (acetic acid buffer) =?
pH of a buffer =?
Let us first find pKa of benzoic acid, knowing that Ka (benzoic acid) = 
So:





Now, using the abovementioned data for the pH formula of a buffer solution or (Henderson-Hasselbalch equation), we have:
![pH = pKa + log\:\dfrac{[salt]}{[acid]}](https://tex.z-dn.net/?f=%20%20pH%20%3D%20pKa%20%2B%20log%5C%3A%5Cdfrac%7B%5Bsalt%5D%7D%7B%5Bacid%5D%7D%20%20%20)





Note:. The pH <7, then we have an acidic solution.
I Hope this helps, greetings ... DexteR! =)
There are two possible products from this elimination:
-2,3-dimethylbut-1-ene
-2,3-dimethylbut-2-ene
As the base is relatively unhindered, the reaction will form the Saytzeff product as the major product. The Saytzeff product is the most substituted alkene which is more stable due to hyperconjugation. In this reaction the Saytzeff product is 2,3-dimethylbut-2-ene.
Answer:
Its answer is cu++ and O-.