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miskamm [114]
3 years ago
10

ammonia reacts with oxygen to produce nitrogen monoxide and water. what volume of nitrogen monoxide will result a complete react

ion with 2800 l of oxygen at stp?
Chemistry
1 answer:
Nina [5.8K]3 years ago
5 0

Answer:

2240L of NO will be produced

Explanation:

First, we need to write a balanced equation for the reaction.

4NH3 + 5O2 —> 4NO + 6H2O

From the equation, it is evident that

5L of O2 produced 4L of NO.

Therefore, 2800L of O2 will produce xL of NO. i.e

xL of NO = (2800x4)/5 = 2240L

Therefore, 2800L of O2 will produce 2240L of NO

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20 mL of an approximately 10% aqueous solution of ethylamine, CH3CH2NH2, is titrated with 0.3000 M aqueous HCl. Which indicator
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Answer:

Therefore, The indicator that is best fit for the given titration is Bromocresol Green Color change from pH between 4.0 to 5.6

Bromocresol green, color change from pH = 4.0 to  5.6

Explanation:

The equation for the reaction is :

C_2H_5NH_2_(_a_q_)     +     H^+_(_a_q_)   ---      C_2H_5NH_{3(aq)}^+

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number of moles of C_2H_5NH_{2(aq) in 20 mL can be determined as:

= 20 mL \times  2.22 M= 44*10^{-3} mole

Concentration of C_2H_5NH_2(aq) = \frac{44*10^{-3}*1000}{20}

= 2.22 M

Similarly, The pKa Value of C_2H_5NH_{2(aq) is given as 10.75

pKb value will be: 14 - pKa

= 14 - 10.75

= 3.25

the pH value at equivalence point is,

pH= \frac{1}{2}pKa - \frac{1}{2}pKb-\frac{1}{2}log[C]

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8 0
3 years ago
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marin [14]

Answer:

Q=113,000J

Explanation:

Hello there!

In this case, since the vaporization process is carried out in order to turn a liquid into a gas due to the addition of heat, we can use the following heat equation involving the heat of vaporization of water or any other substance:

Q=m*\Delta _{vap}H

Thus, since this heat of vaporization for water is 2259.36 J/g, we plug in this amount to obtain the total energy for this process.

Q=50*2259.36 J/g\\\\Q=113,000J

Which is positive due to the necessity of heat.

Regards!

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