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defon
3 years ago
9

how many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia?

Chemistry
2 answers:
kkurt [141]3 years ago
7 0

Answer:

m_{(NH_4)_2SO_4}=7928.4g(NH_4)_2SO_4

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

2NH_3+H_2SO_4-->(NH_4)_2SO_4

Now, by taking into account that 60.0 mol of sulfuric acid are used, the produced grams of ammonium sulfate, by applying the stoichiometric factors, turn out as shown below:

m_{(NH_4)_2SO_4}=60.0molH_2SO_4*\frac{1mol(NH_4)_2SO_4}{1molH_2SO_4} *\frac{132.14g(NH_4)_2SO_4}{1mol(NH_4)_2SO_4} \\m_{(NH_4)_2SO_4}=7928.4g(NH_4)_2SO_4

Best regards.

lianna [129]3 years ago
5 0
2NH3+H2SO4=>(NH4)2SO4
60(1/1)=60mol (NH4)2SO4
1mol=132.14grams
=7928.4grams

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The metallic radius of a potassium atom is 231 pm. What is the volume of a potassium atom in cubic meters?
Sauron [17]
1 pm = 10∧-10 cm
Therefore, 230 pm is equivalent to 2.3 ×10∧-8 cm.
Atom is in the shape of a sphere,
The volume of a sphere is given by 4/3πr³
Thus, volume of the atom = 4/3π( 2.3 ×10∧-8)³
                                          = 4/3 (3.142 ×12.167×10∧-24
                                           = 5.096 ×10∧-23 cm³
but 1m³= 1000000cm³
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8 0
3 years ago
What is the molar ratio for the following equation after it has been properly balanced?
hichkok12 [17]

6 Na + 1 Fe₂O₃ → 3 Na₂O + 6 Fe

<h3>Explanation</h3>

Method One: Refer to electron transfers.

Oxidation states:

  • Na: from 0 to +1; loses one electron.
  • Fe: from +3 to 0; gains three electrons.

Each mole of Fe₂O₃ contains two Fe atoms and will gain 2 × 3 = 6 electrons during the reaction. It takes 6 moles of Na to supply all those electrons.

6 Na + 1 Fe₂O₃ → ? Na₂O + ? Fe

  • There are two moles of Na atoms in each mole of Na₂O. 6 moles of Na will make 3 moles of Na₂O.
  • There are two moles of Fe atoms in each mole of Fe₂O₃. 1 mole of Fe₂O₃ will make 2 moles of Fe.

6 Na + 1 Fe₂O₃ → 3 Na₂O + 2 Fe

Method Two: Atoms conserve.

Fe₂O₃ has the largest number of atoms among one mole of all four species in this reaction. Assume <em>one</em> as its coefficient.

? Na + <em>1</em> Fe₂O₃ → ? Na₂O + ? Fe

There are two moles of Fe atoms and three moles of O atoms in each mol of Fe₂O₃. One mole of Fe₂O₃ contains two moles of Fe and three moles of O. There are one mole of O atom in every mole of Na₂O. Three moles of O will go to three moles of Na₂O.

? Na + <em>1</em> Fe₂O₃ → <em>3</em> Na₂O + <em>2</em> Fe

Each mole of Na₂O contains two moles of Na. Three moles of Na₂O will contain six moles of Na.

<em>6</em> Na + <em>1</em> Fe₂O₃ → <em>3</em> Na₂O + <em>2</em> Fe

Simplify the coefficients. All coefficients in this equation are now full number and relatively prime. Hence the equation is balanced.

6 Na + 1 Fe₂O₃ → 3 Na₂O + 2 Fe

6 0
3 years ago
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4 years ago
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Step2247 [10]
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8 0
3 years ago
Ca+HCI—&gt;CaCI2+H2, what is the reaction?
arsen [322]

Answer:

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Explanation:

This is a kind of single replacement reaction where you switch either cations or anions. Here you switched Ca for H and produced Cacl2 and H2 gas by itself.

4 0
4 years ago
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