how many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia?
2 answers:
Answer:
Explanation:
Hello,
In this case, the undergoing chemical reaction is:
Now, by taking into account that 60.0 mol of sulfuric acid are used, the produced grams of ammonium sulfate, by applying the stoichiometric factors, turn out as shown below:
Best regards.
2NH3+H2SO4=>(NH4)2SO4 60(1/1)=60mol (NH4)2SO4 1mol=132.14grams =7928.4grams
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