Use the equation of -b/2a, so if you have a line you can just plug in the numbers.
Answer:
B is True
A, C. D are false
Step-by-step explanation:
Given :
Sample size, n = 120
Mean diameter, m = 10
Standard deviation, s = 0.24
Confidence level, Zcritical ; Z0.05/2 = Z0.025 = 1.96
The confidence interval represents how the true mean value compares to a set of values around the mean computed from a set of sample drawn from the population.
The population here is N = 10000
To obtain
Confidence interval (C. I) :
Mean ± margin of error
Margin of Error = Zcritical * s/sqrt(n)
Margin of Error = 1.96 * 0.24/sqrt(120)
Confidence interval for the 10,000 ball bearing :
10 ± 1.96 * (0.24) / sqrt(120)
Hence. The confidence interval defined as :
10 ± 1.96 * (0.24) / sqrt(120) is the 95% confidence interval for the mean diameter of the 10,000 bearings in the box.
Answer:
Suppose you have a fair coin: this means it has a 50% chance of landing heads up and a 50% chance of landing tails up. Suppose you flip it three times and these flips are independent. What is the probability that it lands heads up, then tails up, then heads up? So the answer is 1/8, or 12.5%.
0 is in the hundredths place
1 is in the hundreds place
4 is in the ones place
3 is in the tenths place
6 is in the tens place
9 is in the hundred-thousands place
Answer:
The approximate solution to the system is (1.2, 4.4)
x = 1.2 and y = 4.4
Step-by-step explanation:
The solution of the system of linear equations equation y = –0.25x + 4.7 and y = 4.9x – 1.64 is shown in the attached graph. The red line represents the equation y = –0.25x + 4.7 and the blue line represents the equation = 4.9x – 1.64.
The solution of the system of equations is their point of intersection shown on the graph.
The point of intersection is (1.231, 4.392). To the nearest tenth, it is (1.2, 4,4). So x = 1.2 and y = 4.4.
So the approximate solution to the system is (1.2, 4.4)
