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marysya [2.9K]
3 years ago
10

List a possible set of four quantum numbers (n,l,ml,ms) in order, for the highest energy electron in gallium?

Chemistry
1 answer:
Elena-2011 [213]3 years ago
7 0
Gallum: Z = 31

electron configuration: [Ar] 4s^2 3d10 4s2 4p1

Highest energy electron: 4p1

Quantum numbers:

n = 4, because it is the shell number
l = 1, it corresponds to type p orbital 
ml = may be -1, or 0, or +1, depending on space orientation, they correspond to px, py, pz
ms = may be -1/2 or +1/2, this is the spin number. 
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Margaret [11]

Answer:

  1. sodium oxide Nao
  2. aluminum chloride Al2cl3
  3. sodium sulphate Naso4
  4. <em>magnes</em><em>ium</em><em> </em><em>hydroxide</em><em> </em><em>Mgoh2</em>
3 0
3 years ago
Read 2 more answers
The mass percent of solute in a solution containing 3.73 g KBr dissolved in 131 g of H2O is:
Elina [12.6K]

\huge \underbrace \mathfrak \red{Answer}

28%

Explanation:

mass of solute(KBr) = 3.73g

mass of solvent(H2O) = 131g

mass of solution = mass of solute + mass of solvent

= 3.73 + 131

= 134.73g

\sf \large {mass \: percentage =  \frac{mass \: of \: solute}{mass \: of \: solvent}  \times 100} \\  \\  \sf  mass \: percentage =  \frac{3.73}{134.73}  \times 100 \\  \\  \sf mass \: percentage =  0.028 \times 100 \\  \\  \sf mass \: percentage = 28\%

7 0
2 years ago
What is 5.2034 x 10^8 in standard format
777dan777 [17]
Five hundred twenty million, three hundred and forty thousand. hope it helps!

8 0
3 years ago
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The elements lithium and oxygen react explosively to form lithium oxide,Li2O. how many moles of lithium oxide will form if 4.37
anygoal [31]

From the equation,

4 mole of lithium produces 2 mole of lithium oxide

4.37 mol of lithium produces (4.37÷4)x2 mol of lithium oxide

5 0
3 years ago
In the laboratory, a student dilutes 18. 9 ml of a 10. 0 m perchloric acid solution to a total volume of 250. 0 ml. what is the
Sever21 [200]

The concentration of diluted solution is 0.756M.

From the question given above, the following data were obtained:

Volume of stock solution (V1) = 18.9 mL

Molarity of stock solution (M1) = 10 M

Volume of diluted solution (V2) = 250 mL

Molarity of diluted solution (M2) =?

We can obtain the molarity of the diluted solution by using the dilution formula as shown follow:

M1V1 = M2V2

10 × 18.9 = M2 ×250

189 = M2 × 250

Divide both side by 100

M2 = 189 / 250

M2 = 0.756 M

Therefore, the molarity of the diluted solution is 0.756 M.

Thus the concluded that concentration of the dilute acid is 0.756 M.

Learn more about concentration of diluted solution: brainly.com/question/10725862

#SPJ4

7 0
1 year ago
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