Answer: Belongs to the group 2A
Explanation:
As you can see, the first two ionization energies are close and low, meaning that this element ionizates easily.
Not only loses easily the first electron, but the second too
To remove the third electron you requiered a huge amount of energy
Now, elements easily ionizable are the ones from group IA, group 2A and transition metals.
The last ones have mixed characteristics in matter of how many electrons you can remove from them, so they are not a family.
Now the question: group I or group II ?
The elements of group I have low ionization energies for the first electron but high energies for the second ones.
Being all that said, the unknown element belongs to the Group 2A
The math is set up like
35.6 ml * 2.7 g/ 1 ml
which will leave you with
96.12 g
9.5⋅<span>10<span>2
</span></span>Explanation:
To figure out how many atoms of copper you get in 1 gram of copper, you need to use copper's molar mass.
Having resources? i guess...
maybe it is critical thinking?
