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3 years ago

5

At what speed was a train traveling on a trip when it had completed half of the total distance of the trip? (1) the trip was 460

miles long and took 4 hours to complete. (2) the train traveled at an average rate of 115 miles per hour on the trip.

1 answer:

algol133 years ago

5 0

I think 46r is the answer

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PLEASE HELP ME!

andreyandreev [35.5K]

Answer:

12

Step-by-step explanation:

3+5=8

32÷8=4

3×4=12

7 0

3 years ago

Which of the following graphs best represents the solution to the pair of equations below? y = −x + 6 y = 2x − 3 A coordinate pl

Lera25 [3.4K]

The lines are

i) y=-x+6
ii) y=2x-3

The solution of the system of equations is found by equalizing the 2 equations:

-x+6=2x-3

-2x-x=-6-3

-3x=-9

x=-9/(-3)=3

substitute x=3 in either i) or ii):

i) y=-3+6=3
ii) y=2(3)-3=6-3=3

(the result is the same, so checking one is enough)

This means that the point (3, 3) is a point which is in both lines, so a solution to the system.

In graphs, this means that the lines intersect at (3, 3) ONLY

Answer: The graph where the lines intersect at (3, 3)

3 0

4 years ago

Math problem can somebody help!!!!

abruzzese [7]

Answer:

if am correct your answer will be letter d

Step-by-step explanation:

6 0

2 years ago

3xy+x=y-6 how do I solve for y in this?

Tanzania [10]

Answer:

x=y-6/3y+1

Step-by-step explanation:

3xy+x=y−6

Step 1: Factor out variable x.

x(3y+1)=y−6

Step 2: Divide both sides by 3y+1.

x(3y+1)

3y+1

=

y−6

3y+1

7 0

3 years ago

The angle of elevation to the top of a water tower from point A on the ground is 19.9°. From point B, 50.0 feet closer to the to

zepelin [54]

Answer:

Answer in terms of a trigonometric function :

$h = \frac{20tan(19.9)}{0.4-tan(19.9)}$

Answer in figures

$h = 190.5 feet$

Step-by-step explanation:

Consider the sketch attached below to better understand the problem.

Let x be the distance between point B and the base of the water tower.

$tan (19.9)=\frac{h}{50+x} ---------------equation 1\\$

$tan (21.8)=\frac{h}{x}----------------equation 2$

From equation 2,

$x =\frac{h}{tan21.8}=\frac{h}{0.4}$

substituting the value of x into equation 1, we get

$tan (19.9)=\frac{h}{50+(\frac{h}{0.4} )}$

$tan 19.9=h\times \frac{0.4}{20+h}$

cross multiplying,

$20\times tan(19.9) +htan(19.9)=0.4h$

$20tan(19.9)= h(0.4-tan(19.9))$

$h= \frac{20tan (19.9)}{0.4-tan (19.9)}$

The height of the tower is $h= \frac{20tan (19.9)}{0.4-tan (19.9)}$ in terms of the trig function "Tan"

The equation can simply be evaluated to get the answer in figures since the angles are given in the question

5 0

4 years ago