A student pushes a 10 kg box with a force of 30 N at an angle 45 degrees below the horizontal . The box experi 21.2 N of force a
1 answer:
Answer:
Acceleration =0
Explanation:
There are two forces on the box in horizontal direction.
First one is horizontal component of 30N at 45°.
Another one is given in opposite to direction of motion mean opposite to this force.
Which is = 2.22 N
Now we know F (net) =mass*acceleration(center of mass)
21.2-21.2 =10*acceleration
acceleration =0
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Answer:
<em>The final speed of the second package is twice as much as the final speed of the first package.</em>
Explanation:
<u>Free Fall Motion</u>
If an object is dropped in the air, it starts a vertical movement with an acceleration equal to g=9.8 m/s^2. The speed of the object after a time t is:
And the distance traveled downwards is:
If we know the height at which the object was dropped, we can calculate the time it takes to reach the ground by solving the last equation for t:
Replacing into the first equation:
Rationalizing:
Let's call v1 the final speed of the package dropped from a height H. Thus:
Let v2 be the final speed of the package dropped from a height 4H. Thus:
Taking out the square root of 4:
Dividing v2/v1 we can compare the final speeds:
Simplifying:
The final speed of the second package is twice as much as the final speed of the first package.