A student pushes a 10 kg box with a force of 30 N at an angle 45 degrees below the horizontal . The box experi 21.2 N of force a
1 answer:
Answer:
Acceleration =0
Explanation:
There are two forces on the box in horizontal direction.
First one is horizontal component of 30N at 45°.
Another one is given in opposite to direction of motion mean opposite to this force.
Which is = 2.22 N
Now we know F (net) =mass*acceleration(center of mass)
21.2-21.2 =10*acceleration
acceleration =0
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Answer:
e. Not enough information to determine
Explanation:
This question is incomplete. Here is the complete question with my solution afterwards;
A ladybug sits at the outer edge of a turntable, and a gentleman bug sits halfway between her and the axis of rotation. The turntable (initially at rest) begins to rotate with its rate of rotation constantly increasing.
What is the first event that will occur?(Assume non-zero frictional force and the same coefficients of friction for both bugs.)
a. The ladybug begins to slide
b. The gentleman bug begins to slide
c. Both bugs begin to slide at the same time
d. Nothing ever happens
e. Not enough information to determine
The centripetal force acting on a rotating body or bugs can be written as,
mass of the corresponding bugs
corresponding radial distance of each bug
angular speed of the turntable
The centripetal force tries to slide the bugs in an outward direction and it is directly proportional to the products of its mass and radial distance from the axis of rotation of the turntable
∝
Since the radial distance from the axis of rotation of the turntable for each bug is given, but the mass is not given, the given information is therefore not enough to determine which bugs will slide first.
Option "e" is correct.