Answer:
(a). Energy is 64,680 J
(b) velocity is 51.43m/s
(c) velocity in mph is 115.0mph
Explanation:
(a).
The potential energy of the payload of mass
is at a vertical distance
is
.
Therefore, for the payload of mass at a vertical distance of
, the potential energy is
(b).
When the payload reaches the bottom of the shaft, all of its potential energy is converted into its kinetic energy; therefore,
(c).
The velocity in mph is
The kinetic energy of the child at the bottom of the incline is 106.62 J.
The given parameters:
The vertical height of fall of the child from the top of the incline is calculated as;
The gravitational potential energy of the child at the top of the incline is calculated as;
Thus, based on the principle of conservation of mechanical energy, the kinetic energy of the child at the bottom of the incline is 106.62 J since no energy is lost to friction.
Learn more about conservation of mechanical energy here: brainly.com/question/332163