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Xelga [282]
3 years ago
7

If 56.8 ml of bacl2 solution is needed to precipitate all the sulfate ion in a 554 mg sample of na2so4 (forming baso4), what is

the molarity of the solution?
Chemistry
1 answer:
IrinaVladis [17]3 years ago
3 0
<span>0.0687 m The balanced equation is BaCl2 + Na2SO4 ==> BaSO4 + 2 NaCl Looking at the equation, it indicates that there's a 1 to 1 ratio of BaCl2 and Na2SO4 in the reaction. So the number of moles of each will be equal. Now calculate the number of moles of Na2SO4 we had. Start by looking up atomic weights. Atomic weight sodium = 22.989769 Atomic weight sulfur = 32.065 Atomic weight oxygen = 15.999 Molar mass Na2SO4 = 2 * 22.989769 + 32.065 + 4 * 15.999 = 142.040538 g/mol Moles Na2SO4 = 0.554 g / 142.040538 g/mol = 0.003900295 mol Molarity is defined as moles per liter, so let's do the division. 0.003900295 mol / 0.0568 l = 0.068667165 mol/l = 0.068667165 m Rounding to 3 significant figures gives 0.0687 m</span>
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3 years ago
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Electron configuration is the number of electrons that are present in the atom and is repressed through the different sub-shells. So for example, the electron configuration for oxygen is 1s^2 2s^2 2p^4. While the valence electrons only refer to the electrons in the outermost shell of the atom.

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4 0
2 years ago
Carbon has two naturally occurring isotopes: C-12 (natural abundance is 98.93%) and C-13 (natural abundance is 1.07%). How many
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Explanation:

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Explanation:

3 0
2 years ago
Read 2 more answers
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