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3 years ago

Balance _Mg + _HCL = _MgCl2 + H2

2 answers:

5 0

_Mg + _HCL = _MgCl2 + H2
Separate the terms on each side:

_Mg + _HCl = _MgCl2 + H2

Mg- 1 Mg-1

H-1 H-2

Cl-1 Cl-2

Mg is balanced on both sides so move on to the next (put a 1 in the space).

1Mg

There are two H's and two Cl's on the results side, so to balance the equation put a 2 as a coefficient for HCl and it'll all balance out.

2HCl

Balamced equation will be:

1Mg + 2HCL = 1MgCl2 + H2

ivann1987 [24]3 years ago

3 0

1 Mg + 2 HCl ----> 1 MgCl2 + 1 H2

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How many moles of O₂ are needed to react completely with 35.0 mol of FeCl₃? *

galben [10]

Answer:

52.5 mol O2

Explanation:

4 FeCl3 + 6 O2 -> 2 Fe2O3 +6 Cl2

4 mol FeCl3 -> 6 mol O2

35.0 mol FeCl3 -> x

x= (35.0 mol FeCl3 * 6 mol O2)/4 mol FeCl3

x=52.5 mol O2

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3 years ago

Read 2 more answers

How much energy is required to raise the temperature of 10.7 grams of gaseous helium from 22.1 °C to 39.4 °C ?

Rainbow [258]

Answer:

Q = 2640.96 J

Explanation:

Given data:

Mass of He gas = 10.7 g

Initial temperature = 22.1°C

Final temperature = 39.4°C

Heat absorbed = ?

Solution:

Specific heat capacity:

It is the amount of heat required to raise the temperature of one gram of substance by one degree. Specific heat capacity of He is 14.267 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = 39.4°C - 22.1°C

ΔT = 17.3°C

Q = 10.7 g× 14.267 J/g.°C × 17.3°C

Q = 2640.96 J

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3 years ago

In a sample of solid ba(no3)2 the ratio of barium ions to nitrate ions is

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I believe the ratio is 1:2

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4 years ago

Problem PageQuestionSteam reforming of methane ( ) produces "synthesis gas," a mixture of carbon monoxide gas and hydrogen gas,

Serhud [2]

The question is incomplete. Her eis the complete question.

Steam reforming methane (CH4) produces "synthesis gas", a mixture of carbon monoxide gas and hydrogen gas, which is the starting point for many important industrial chemical syntheses. An industrial chemist studying this reaction fills a 125L tank with 20 mol of methane gas and 10 mol of water vapor at 38°C. He then raises the temperature, and when the mixture has come to equilibrium measures the amount of gas hydrogen to be 18 mol. Calculate the concentration equilibrium constant for the steam reforming of methane at the final temperature of the mixture. Round your answer to significant digits.

Answer: $K_{c}$ = 2. $10^{-2}$

Explanation: The reaction for steam reforming methane is:

$CH_{4} + H_{2}O$ ⇒ $CO_{} + 3H_{2}$

To calculate the concentration equilibrium constant, first calculate the molarity ( $\frac{mol}{L}$ ) of each molecule of the reaction.

At 38°C: At the initial temperature, there no products yet

Molarity of CH4:

CH4 = $\frac{20}{125}$ = 0.16M

Molarity of H20:

H2O = $\frac{10}{125}$ = 0.08M

At final temperature:

Molarity of H2:

H2 = $\frac{18}{125}$ = 0.144M

According to the chemical reaction, the combination of 1 mol of each reagents produces 1 mol of CO and 3 mols of H2, so, for the products, the ratio is 1:3.

Molarity of CO:

CO = $\frac{0.144}{3}$ = 0.048M

For the reagents, the proportion is 1:1, but they had an initial concentration, so, when in equilibrium, the concentration will be:

Molarity of CH4:

CH4 = 0.16 - 0.048 = 0.112M

Molarity of H2O:

H20 = 0.08 - 0.048 = 0.032M

The equilibrium constant is given by:

$K_{c} = \frac{[CO][H_{2}]^{3} }{[CH_{4}][H_{2}O ] }$

$K_{c}$ = $\frac{0.048.0.144^{3} }{0.112.0.032}$

$K_{c}$ = 2. $10^{-2}$

The concentration equilibrium constant for the process is $K_{c}$ = 2. $10^{-2}$ .

4 0

3 years ago

Classify these definitions as that of an Arrhenius acid, an Arrhenius base, or other. Arrhenius acid definition Arrhenius base d

stealth61 [152]

Answer:

Explanation:

A substance that produces an excess of hydroxide ion (-OH) in aqueous solution.

This is an arrhenius Base

According to the arrhenius theory, a base is a substance that combines with water to produce excess hydroxide ions, OH⁻ in an aqeous solution. Examples are :

Sodium hydroxide NaOH
Potassium hydroxide KOH

A substance that produces an excess of hydrogen ion (H+) in aqueous solution

This is an arrhenius Acid

An arrhenius acid is a substance that reacts with water to produce excess hydrogen ions in aqueous solutions.

Examples are;

Hydrochloric acid HCl
Hydroiodic acid HI
Hydrobromic acid HBr

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4 years ago