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2 years ago

3. Analizando la siguiente reacción química de formación del agua:

Chemistry

1 answer:

Leya [2.2K]2 years ago

5 0

Answer:

3. Analizando la siguiente reacción química de formación del agua:

2 H2 (g) + O2 (g)  2 H2O (l)

Si se hacen reaccionar 10 g de hidrógeno con 10 g de oxígeno:

a) Plantee las razones molares de dicha ecuación

b) Determine si se consumen la totalidad de dichos reactivos. Demuéstrelo con los cálculos estequiométricos correspondientes.

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Which energy transformation is represented in the diagram?

Paha777 [63]

A nuclear to thermal and radiant

Explanation:

Nuclear fission is the disintegration of the force that holds the nucleus of the atom together, creating two different but lighter nuclei.

In nuclear fission, it seeks to break the force of attraction or nuclear force that joins the protons and neutrons that form the nucleus of an atom. Neutrons without electric charge are used against the nucleus of the atom to produce enough excitation energy to deform the nucleus into two halves.

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2 years ago

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Investigate and explain that when a force is applied to an object but it does not move, it is because another opposing force is

N76 [4]

Answer:

4. Force 1 Force 2 Comparison of Forces

Friction Gravity Force 1 is equal to Force 2

Explanation:

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2 years ago

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2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2

nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with $H_2$ to form $CH_4$ and $H_2O$ . balanced reaction is:

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

No. of moles of CO = 0.800 mol

No. of moles of $H_2$ = 2.40 mol

Volume = 8.00 L

Concentration = $\frac{Moles}{Volume\ in\ L}$

Concentration of CO = $\frac{0.800}{8.00} = 0.100\ mol/L$

Concentration of $H_2$ = $\frac{2.40}{8.00} = 0.300\ mol/L$

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

Initial 0.100 0.300 0 0

equi. 0.100 -x 0.300 - 3x x x

It is given that,

at equilibrium $H_2O (x)$ = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium $H_2$ = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium $CH_4$ = 0.0386 M

$Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}$

$Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90$

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3 years ago

Which of the following types of rocks are likely to be formed due to compacting and cementing?

blagie [28]

Answer:

Sedimentary only

Explanation:

when compacting and cementing happens then a sedimentary rock can and is made!

hope this helps!

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2 years ago

Which of the following occurs when an electron moves from a higher energy shell to a lower energy shell?

AlexFokin [52]

When an electron moves from a higher energy shell to a lower one, energy in the form of light, more specifically a wavelength of a photon is released.

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2 years ago