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victus00 [196]
3 years ago
13

Does an acid gain or lose a hydrogen cation, H+, during an acid-base reaction?

Chemistry
1 answer:
elena-s [515]3 years ago
6 0

It loses an H+.

The bronsted lowry definition for an acid is that an acid is a H+ donor, or giver. So, during an acid based reaction, an acid would lose a H+.

Lose an H+.

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When benzene (c6h6) reacts with bromine (br2) bromobenzene(c6h5br) is obtained: c6h6 + br2 → c6h5br + hbr what is the theoretica
saveliy_v [14]

Answer A) : We have to calculate the number of moles of Benzene involved in the reaction,

30 g / 78 moles of benzene = 0.384 moles


For bromine it will be the same process,

65 g / 159.8 moles = 0.406 moles


By observing the reaction given above we can say that the reaction ratio of bromine and benzene is 1 : 1


We need to find the mass of bromobenzene,

which should be, 6(12) + 5 (1)+ 79.90 = 156.9 g/mol


So, the mass of bromobenzene will be 156.9 g/mol X 0.3846 mol = 60.343 g


Hence the theoretical yield will be 60.34 g


Answer B) : To calculate the actual yield we have to divide it with theoretical yield.


(56.7g / 60.343 g ) X100% = 93.96 %


Here, we can say that we got 93.96 % of actual yield.


As we know it is impossible to get 100% yield in any reaction.

3 0
3 years ago
Convert the following<br> 4. 100 cm =<br> 5. 453 m = _<br> 6. 89847nm = _<br> 7. 3Mm =
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6 0
3 years ago
Linolenic acid (C18H30O2 - M.W. = 278.42 g/mol) reacts with hydrogen gas according to the equation: C18H30O2 + 3H2 (g) → C18H36O
Ludmilka [50]

Answer:

2.53 L is the volume of H₂ needed

Explanation:

The reaction is: C₁₈H₃₀O₂ + 3H₂ → C₁₈H₃₆O₂

By the way we can say, that 1 mol of linolenic acid reacts with 3 moles of oxygen in order to produce, 1 mol of stearic acid.

By stoichiometry, ratio is 1:3

Let's convert the mass of the linolenic acid to moles:

10.5 g . 1 mol / 278.42 g  = 0.0377 moles

We apply a rule of three:

1 mol of linolenic acid needs 3 moles of H₂ to react

Then, 0.0377 moles will react with (0.0377 . 3 )/1 = 0.113 moles of hydrogen

We apply the Ideal Gases Law to find out the volume (condition of measure are STP) → P . V = n . R . T → V = ( n . R .T ) / P

V = (0.113 mol . 0.082 L.atm/mol.K . 273.15K) 1 atm = 2.53 L

4 0
3 years ago
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