Answer:
Magnitude of the force is 2601.9 N
Explanation:
m = 450 kg
coefficient of static friction μs = 0.73
coefficient of kinetic friction is μk = 0.59
The force required to start crate moving is 
.
but once crate starts moving the force of friction is reduced .
Hence to keep crate moving at constant velocity we have to reduce the force pushing crate ie .
Then the above pushing force will equal the frictional force due to kinetic friction and constant velocity is possible as forces are balanced.
Magnitude of the force
s=600 m
t=12 s
s=0.5*a*t² (initial speed V0=0)
a=(2*s)/t²
a=(2*600)/12²
a≈8.33 m/s²
L= s(t2=12s)-s(t1=11s) -> (distance during the twelfth second)
L=0.5*a*(t2²-t1²)
L=0.5*((2*s)/t²)*(t2²-t1²)
L=0.5*((2*600)/12²)*(12²-11²)
L ≈ 95.83 m
Answer:
3,13 N
Explanation:
Del enunciado de la segunda ley del movimiento de Newton;
F = ma
Dónde;
F = Fuerza aplicada
m = masa del cuerpo
a = aceleración del cuerpo
Sustitución de valores;
F = 5,9 kg * 0,53 m / seg2 = 3,13 N
Por tanto, la fuerza aplicada es 3,13 N
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Answer:
c) Twice as much
Explanation:
As we know that kinetic energy is given by the formula
here we know that
m = mass of the object
v = speed of the object
so here we will have kinetic energy of Car A
now we have kinetic energy of B is given as
So kinetic energy of Car A is double that of Kinetic energy of car B
