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Komok [63]
3 years ago
7

A ballon falls from rest. it gains a velocity of 30m/s during an interval of 3second. what is the acceleration due to gravity at

the place from which it falls? And what is the displacement it covers during this time interval?​

Physics
1 answer:
Step2247 [10]3 years ago
7 0

Answer:

the acceleration due to gravity is 10ms-1

displacement=time*velocity

d=3*30=90ms-1

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4 years ago
Radar uses radio waves of a wavelength of 2.4 \({\rm m}\) . The time interval for one radiation pulse is 100 times larger than t
blondinia [14]

Answer:

120 m

Explanation:

Given:

wavelength 'λ' = 2.4m

pulse width 'τ'= 100T ('T' is the time of one oscillation)

The below inequality express the range of distances to an object that radar can detect

τc/2 < x < Tc/2 ---->eq(1)

Where, τc/2 is the shortest distance

First we'll calculate Frequency 'f' in order to determine time of one oscillation 'T'

f = c/λ (c= speed of light i.e 3 x 10^{8} m/s)

f= 3 x 10^{8} / 2.4

f=1.25 x  10^{8} hz.

As, T= 1/f

time of one oscillation T= 1/1.25 x  10^{8}

T= 8 x 10^{-9} s

It was given that pulse width 'τ'= 100T

τ= 100 x 8 x 10^{-9} => 800 x 10^{-9} s

From eq(1), we can conclude that the shortest distance to an object that this radar can detect:

x_{min}= τc/2 =>  (800 x 10^{-9} x 3 x 10^{8})/2

x_{min}=120m

8 0
4 years ago
A ball of mass 0.15 kg is dropped from rest from a height of 1.25 m. It rebounds from the floor to reach a height of 0.960 m. b)
Art [367]

Answer:

Explanation:

If v be the velocity just after the rebound

Kinetic energy will be converted into potential energy

1/2 m v² = mgh

v² = 2gh

v = √ 2gh

= √ 2 x 9.8 x .96

= 4.33 m / s

4 0
3 years ago
An object that has negative acceleration is definitely doing what?
krek1111 [17]

If an object is consist of a negative acceleration or composed of it, it is likely engaging of having to accelerate in a certain direction in which the direction is heading towards the opposite of the direction that is stated and that is likely to be a positive direction.

3 0
4 years ago
What is stopping distance of a body at 20 m/s is decelerated at 2m/s² to rest?<br>​
AlladinOne [14]

Answer:

s = 100 m

Explanation:

v² = u² + 2as

s = (v² - u²) / 2a

s = (0² - 20²) / 2(-2)

s = 100 m

5 0
3 years ago
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