Answer:
A general line can be represented as , y= m x + c
And general equation of circle is , ax²+by²+2 g x +2 f y +c=0
Now there are following possibilities
1. A line and circle have no common point of intersection, that is no solution.
2. A line may be a tangent to a circle, that is one common point, one solution.
3. A line may intersect a circle maximum at two points, that is 2 solution.
Image is depicted below.
d =sqrt ((x2-x1)^2 +(y2-y1)^2)
sqrt((12-2)^2 +(7--3)^2)
sqrt(10^2+10^2)
sqt(100+100)
sqrt(200)
sqrt(100)sqrt(2)
10sqrt(2)
Choice B
Answer:
Gradient of A: 2
Gradient of B: -1
Step-by-step explanation:
Gradient = change in y/change in x
✔️Gradient of A using two points on line A, (2, 5) and (0, 1):
Gradient = (1 - 5)/(0 - 2) = -4/-2
Simplify
Gradient of A = 2
✔️Gradient of B using two points on line B, (0, 5) and (5, 0):
Gradient = (0 - 5)/(5 - 0) = -5/5
Simplify
Gradient of B = -1
Total Area = Lateral Area + Area of the Ends
Total Area = Height * Width * Number of Sides + Area of the 2 ends
