Formula units in 450 g of is 1.93 × 10²⁴ formula units.
<u>Explanation:</u>
First we have to find the number of moles in the given mass by dividing the mass by its molar mass as,
Now, we have to multiply the number of moles of Na₂SO₄ by the Avogadro's number, 6.022 × 10²³ formula units/mol, so we will get the number of formula units present in the given mass of the compound.
3.2 mol × 6.022 × 10²³ = 1.93 × 10²⁴ formula units.
So, 1.93 × 10²⁴ formula units is present in 450g of Na₂SO₄.
75 g of sodium hydroxide is present in the solution.
<u>
</u><u>Explanation</u><u>
:</u>
Given
:
Molarity of sodium hydroxide solution= 2.5 M
Litres of Solution = 750 mL
Molar mass of NaOH = 40 g/mol
To Find:
Grams of Sodium Hydroxide =?
Solution
:
Molarity of the solution is expressed in Litres, So Converting 750.0 mL to Litres we have
750.0mL=0.750 Litres
Grams of Solution
, moles=
Where
M = Molarity
L = litres of solution
mol= moles of solute
Mol = 1.875
Also the molecular weight of NaOH is 40.00 g/mol
Grams of sodium hydroxide = 1.875 mol * 40.00 g/mol = 75 g
If the ball is dropped from a higher height than the feather their rates of displacement (acceleration) could match.