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3 years ago

Is a microvilli is a tiny finger like projection that kills bacteria in the lymphatic system? true or false

1 answer:

5 0

Villi are tiny finger like projections present in the inner epithelial lining of the intestine. Each finger like villi is further divided into microvilli, which is the extension of plasma membrane of each epithelial cell of the villi. These villi and microvilli present on the inner surface of the intestine provide a greater surface area and this enhances the digestion and absorption of the nutrients.

Therefore, the correct answer is false as a microvilli is the tiny finger like projection of the inner epithelial cells of the small intestine that has absorptive functions.

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Which term is used to describe all the habitats around the world?

OlgaM077 [116]

Answer:

ecosystem diversity

Explanation:

hope this helped

5 0

1 year ago

Write empirical formula

andrew11 [14]

Answer:

$Pb(ClO_{3})_{4}\\Pb(MnO_{4})_{4}\\Fe(ClO_{3})_{3}\\\Fe(MnO_{4})_{3}\\$

Explanation:

$Pb^{4+}(ClO_{3}^{-})_{4}--->Pb(ClO_{3})_{4}\\Pb^{4+}(MnO_{4}^{-})_{4}--->Pb(MnO_{4})_{4}\\Fe^{3+}(ClO_{3}^{-})_{3}--->Fe(ClO_{3})_{3}\\\Fe^{3+}(MnO_{4}^{-})_{3}--->Fe(MnO_{4})_{3}\\$

3 0

3 years ago

Balance the following reaction:

kvv77 [185]

C_5H_8+13/2O_2—»5CO_2+4H_2O

Balanced one

2C_5H_8+13O_2—»10CO_2+8H_2O

Moles of Pentyne

Given mass/Molarmass
34/68
0.5mol

Moles of H_2O

8/2(0.5)
4(0.5)
2mol

1mol releases 241.8KJ

2mol releases 241.8(2)=483.6KJ

8 0

2 years ago

A useful single-displacement reaction involves thermite, which is a

Licemer1 [7]

The reaction of iron (III) oxide and aluminum is initiated by heat released from a small amount "starter mixture". This reaction is an oxidation-reduction reaction, a single replacement reaction, producing great quantities of heat (flame and sparks) and a stream of molten iron and aluminum oxide which pours out of a hole in the bottom of the pot into sand.

The balanced chemical equation for this reaction is:

2 Al(s) + Fe2O3(s) --> 2Fe(s) + Al2O3(s) + 850 kJ/mol

Curriculum Notes
This chemical reaction can be used to demonstrate an exothermic reaction, a single replacement or oxidation-reduction reaction, and the connection between ∆H calculated for this reaction using heats of formation and Hess' Law and calculating ∆H for this reaction using qrxn = mc∆T and the moles of limiting reactant. This reaction also illustrates the role of activation energy in a chemical reaction. The thermite mixture must be raised to a high temperature before it will react.

To determine how much thermal energy is released in this reaction, heats of formation values and Hess' Law can be used.

By definition, the deltaHfo of an element in its standard state is zero.

2 Al(s) + Fe2O3(s) --> 2Fe (s) + Al2O3 (s)

The deltaH for this reaction is the sum of the deltaHfo's of the products - the sum of the deltaHfo's of the reactants (multiplying each by their stoichiometric coefficient in the balanced reaction equation), i.e.:

deltaHorxn = (1 mol)(deltaHfoAl2O3) + (2 mol)(deltaHfoFe) - (1 mol)(deltaHfoFe2O3) - (2 mol)(deltaHfoAl)

deltaHorxn = (1 mol)(-1,669.8 kJ/mol) + (2 mol)(0) - (1 mol)(-822.2 kJ/mol) - (2mol)(0 kJ/mol)

deltaHorxn = -847.6 kJ

The melting point of iron is 1530°C (or 2790°F).
MARK ME BRAINLIEST

7 0

2 years ago

Based on the position of the elements in the periodic table, what is the charge of the ions they are most likely to form?

Rainbow [258]

Explanation:

The charge on an ion denotes the amount of electrons lost or gained or even shared by an atom.

An atom will lose, gain or share an equal amount of electrons that will make it stable and achieve an octet and perfect configuration.

This is often synonymous with the component number of electrons in their outermost shell. The valence shell.

For metals on the periodic table, they are always willing to give up electrons due to their large electropositivity.

Metals will give up the number of electrons in their outermost shell to become stable.

Groups 1 and Group 2 will have charges +1 and +2 on them.

For non-metals , they will gain the exact number of electrons that will make them stable. We must note that half -filled and fully filled orbitals are equally stable.

Elements in groups 6 and 7 are electronegative and will have a charge of -2 and -1 respectively.

For those in groups 3, 4 and 5 they either gain, lose or share commensurate amount of electrons that will make them stable.

Group 8 elements are stable and have no charges.

Generally on the periodic table, metals are to the left and are always positively charged. Non - metals are to the right and are negatively charged.

learn more:

Periodic table brainly.com/question/2690837

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4 0

3 years ago