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garri49 [273]
3 years ago
8

A thermodynamically unfavorable reaction can become favorable when coupled to a highly ________ reaction. A thermodynamically un

favorable reaction can become favorable when coupled to a highly ________ reaction. Ionic Exergonic Neutral Endergonic
Chemistry
1 answer:
amid [387]3 years ago
6 0

Answer:

Ionic Exergonic

Explanation:

Exergonic reactions have negative Gibbs free energy and hence are spontaneous.

Endergonic reactions have negative Gibbs free energy and are non-spontaneous and low temperature.

Endergonic reactions require external supply of energy. But such reactions can be made spontaneous or favorable by coupling with exergonic reaction via a common intermediate.

Therefore, the correct answer is Ionic Exergonic.

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What will happen to density of urine when a diabetic excretes too much sugar ?
pishuonlain [190]

The density of urine decreases when a diabetic secretes too much sugar.

When there is excess sugar in the blood, the kidneys release extra water.

The result is a <em>more dilute</em> and therefore <em>less dense urine</em>.

The urine from a non-diabetic person usually has a density of 1.010 g/mL to 1.025 g/mL.

The urine from a diabetic person often has a density less than 1.008 g/mL.

5 0
3 years ago
Trimix 10/50 is a gas mixture that contians 10% oxygen and 50% helium, and the rest is nitrogen. If a tank of trimix 10/50 has a
Marat540 [252]

Answer : The partial pressure of helium is, 1.815\times 10^4KPa

Solution : Given,

Molar mass of O_2 = 32 g/mole

Molar mass of helium = 4 g/mole

Molar mass of N_2 = 28 g/mole

Total pressure of gas = 2.07\times 10^4KPa

As we are given gases in percent, that means 10 g of oxygen gas, 50 g of helium gas and 40 g of nitrogen gas present in 100 g of mixture.

First we have to calculate the moles of oxygen, helium and nitrogen gas.

\text{Moles of }O_2=\frac{\text{Mass of }O_2}{\text{Molar mass of }O_2}=\frac{10g}{32g/mole}=0.3125moles

\text{Moles of }He=\frac{\text{Mass of }He}{\text{Molar mass of }He}=\frac{50g}{4g/mole}=12.5moles

\text{Moles of }N_2=\frac{\text{Mass of }N_2}{\text{Molar mass of }N_2}=\frac{40g}{28g/mole}=1.428moles

Now we have to calculate the total number of moles of gas mixture.

\text{Total number of moles of gas}=\text{Moles of oxygen gas}+\text{Mole of helium gas}+\text{Moles of nitrogen gas}

\text{Total number of moles of gas}=0.3125+12.5+1.428=14.24moles

Now we have to calculate the moles fraction of helium gas.

\text{Mole fraction of He gas}=\frac{\text{Moles of He gas}}{\text{Total number of moles of gas}}=\frac{12.5}{14.25}=0.877

Now we have to calculate the partial pressure of helium.

p_{He}=X_{He}\times P_T

where,

p_{He} = partial pressure of helium

P_T = total pressure

X_{He} = mole fraction of helium

Now put all the given values in this formula, we get

p_{He}=(0.877)\times (2.07\times 10^4KPa)=1.815\times 10^4KPa

Therefore, the partial pressure of helium is, 1.815\times 10^4KPa

8 0
3 years ago
PLEASE HELP ITS VERY EASY FOR OTHER PLEASE ITS A TEST DUE IN AN HOUR PLEASEEEEEEEEEE
STatiana [176]

Answer:

I think it is three times I'm not sure

5 0
3 years ago
Read 2 more answers
Sam places 5 g of baking soda in 5 g of liquid vinegar, and notices fizzing. After all the fizzing stops, 5 g of liquid remains.
anygoal [31]
Answer: G

5+5=10

10-5=5

5 g of gas escaped
3 0
3 years ago
Read 2 more answers
. In which reaction is nitric acid acting as an oxidising agent?
Talja [164]

Answer:

B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2

Explanation:

Hello,

In this case, we should understand oxidizing agents as those substances able to increase the oxidation state of another substance, therefore, in B. reaction we notice that copper oxidation state at the beginning is zero (no bonds are formed) and once it reacts with nitric acid, its oxidation states raises to +2 in copper (II) nitrate, thus, in B. Cu + 4HNO3 → Cu(NO3)2 + 2H2O + 2NO2 nitritc acid is acting as the oxidizing agent.

Moreover, in the other reactions, copper (A.), sodium (C. and D.) remain with the same initial oxidation state, +2 and +1 respectively.

Regards.

8 0
3 years ago
Read 2 more answers
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