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bazaltina [42]
3 years ago
15

Alguien sabe algo de introducción ala fisica ?​

Chemistry
1 answer:
pshichka [43]3 years ago
3 0

Answer: Un ala es un tipo de aleta que produce elevación, mientras se mueve a través del aire o algún otro fluido. Como tal o puede calcularse a partir de la distribución de velocidad aérea utilizando principios físicos básicos

Explanation:

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How many joules of heat are needed to raise the temperature of 10.0 g of aluminum from 22°C to 55°C, if the specific heat of alu
Sergio039 [100]

Answer:

297

Explanation:

55-22=33

Then use 33 *10*0.9

5 0
3 years ago
The intersection angle of a 3 degree curve is 45.2 degrees. What is the length of the curve? of Select one: O a. 455 m O b.573 m
ValentinkaMS [17]

Explanation:

Relation between length of a curve and angle is as follows.

               l = R \times \Theta

where,   R = radius of curve

         \Theta = angle in radians

Also,     l = R \times \Theta \times \frac{\pi}{180}  .......... (1)

If curve has a degree of curvature D_{a} for standard length s, then

               R = \frac{s}{D_{a}} \times \frac{180}{\pi}   ........... (2)

Now, substitute the value of R from equation (2) into equation (1) as follows.

               l = \frac{s \times \Theta}{D_{a}}  

If s = 30 m, then calculate the value of l as follows.

                 l = \frac{s \times \Theta}{D_{a}}  

                   = 30 \times \frac{45.2}{3}              

                   = 452 m

thus, we can conclude that the length of the curve is 452 m.

7 0
3 years ago
Aluminium +hydrochloride acid ________+_________​
REY [17]

Answer:

Aluminium Chloride + Hydrogen

Please vote for Brainliest and I hope this helps!

4 0
2 years ago
how many kilograms of a 35% m/m sodium chlorate solution is needed to react completely with 0.29 l of a 22% m/v aluminum nitrate
Stolb23 [73]

Answer:- 0.273 kg

Solution:- A double replacement reaction takes place. The balanced equation is:

3NaClO_3+Al(NO_3)_3\rightarrow 3NaNO_3+Al(ClO_3)_3

We have 0.29 L of 22% m/v aluminum nitrate solution. m/s stands for mass by volume. 22% m/v aluminium nitrate solution means 22 g of it are present in 100 mL solution. With this information, we can calculate the grams of aluminum nitrate present in 0.29 L.

0.29L(\frac{1000mL}{1L})(\frac{22g}{100mL})

= 63.8 g aluminum nitrate

From balanced equation, there is 1:3 mol ratio between aluminum nitrate and sodium chlorate. We will convert grams of aluminum nitrate to moles and then on multiplying it by mol ratio we get the moles of sodium chlorate that could further be converted to grams.

We need molar masses for the calculations, Molar mass of sodium chlorate is 106.44 gram per mole and molar mass of aluminum nitrate is 212.99 gram per mole.

63.8gAl(NO_3)_3(\frac{1mol}{212.99g})(\frac{3molNaClO_3}{1molAl(NO_3)_3})(\frac{106.44g}{1mol})

= 95.7gNaClO_3

sodium chlorate solution is 35% m/m. This means 35 g of sodium chlorate are present in 100 g solution. From here, we can calculate the mass of the solution that will contain 95.7 g of sodium chlorate  and then the grams are converted to kg.

95.7gNaClO_3(\frac{100gSolution}{35gNaClO_3})(\frac{1kg}{1000g})

= 0.273 kg

So, 0.273 kg of 35% m/m sodium chlorate solution are required.

7 0
3 years ago
How much does the air weigh within a column that is 1 square inch in area that extends from sea level all the way to the top of
fredd [130]

Answer:

14.7 lbs

Explanation:

Air pressure is the weight of the air above us. It is approximately 14.7 pounds or lbs per square inch at sea level. It means that an air column weights 14.7 lbs, 1 square inch in diameter, reaching all the way up to the top of the atmosphere.

5 0
3 years ago
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