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1 year ago

Pls helps asap plssss !!!!

Chemistry

2 answers:

DerKrebs [107]1 year ago

5 0

Answer:1 3 4 1 im pretty positive

padilas [110]1 year ago

4 0

Answer: B) 1, 2, 2, 1

Explanation:

Because copper nitrate requires two nitrate, the minimum amount of nitrate is 2. Thus, you must have 2 silver nitrate, and 2 silver.

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Describe the structure of atoms including the masses, electrical, charges, and locations of protons, neutrons in the nucleus ,an

steposvetlana [31]

Answer:

The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).

Explanation:

The nucleus (center) of the atom contains the protons (positively charged) and the neutrons (no charge).

3 0

2 years ago

What is the molarity of a 9.13 L soda that contains 13.83 of sugar?

choli [55]

Answer:

1.52 M

Explanation:

Molarity of a solution is calculated as follows:

Molarity = number of moles (n) ÷ volume (V)

Based on the information given in this question,

Volume of soda (V) = 9.13 L

number of moles = 13.83 mol

Molarity = 13.83 ÷ 9.13

Molarity = 1.52 M

7 0

2 years ago

The number of electrons in a neutral atom of hydrogen (H) atom is

vesna_86 [32]

There is one electron

7 0

2 years ago

How many grams of helium must be released to reduce the pressure to 65 atmatm assuming ideal gas behavior? Express the answer in

lyudmila [28]

The question is incomplete, here is the complete question:

How many grams of helium must be released to reduce the pressure to 65 atm assuming ideal gas behavior. Note : 334-mL cylinder for use in chemistry lectures contains 5.209 g of helium at 23°C.

Answer: The mass of helium released is 1.6 grams

Explanation:

We are given:

Mass of helium in the cylinder = 5.209 g

To calculate the number of moles, we use the equation given by ideal gas equation:

PV = nRT

Or,

$PV=\frac{w}{M}RT$

where,

P = Pressure of the gas = 65 atm

V = Volume of the gas = 334 mL = 0.334 L (Conversion factor: 1 L = 1000 mL)

w = Weight of the gas = ?

M = Molar mass of helium gas = 4 g/mol

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = Temperature of the gas = $23^oC=[23+273]K=296K$

Putting values in above equation, we get:

$65atm\times 0.334L=\frac{w}{4g/mol}\times 0.0821\text{ L atm }mol^{-1}K^{-1}\times 296K\\\\w=\frac{65\times 0.334\times 4}{0.0821\times 296}=3.573g$

Mass of helium released = (5.209 - 3.573) g = 1.636 g = 1.6 g

Hence, the mass of helium released is 1.6 grams

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2 years ago

1)Fe+ Cl2 → FeCl, How to balance this 2)Fe+ O2 →Fe2O3 How to balance this

Agata [3.3K]

2Fe + Cl₂ -> 2FeCl
4Fe + 3O₂ -> 2Fe₂O₃

4 0

2 years ago

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