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Ilia_Sergeevich [38]
3 years ago
10

How many molecules are in 10 grams of sugar?

Chemistry
1 answer:
elena-s [515]3 years ago
4 0

Answer:

A sugar cube is supposed to be equivalent to a teaspoon of sugar. A teaspoon of sugar is about 4.2 g. Table sugar is composed of sucrose, which is a disaccharide of glucose and fructose, with a molar mass of 342.3 g/mol. This means a sugar cube contains (4.2 / 342.3 =) 0.0123 mol of sucrose, or (0.0123 x 6.022 x 10^23 =) 7.39 x 10^21 molecules of sucrose. As one molecule of sucrose contains one molecule of glucose and one molecule of fructose, then there about 7,400 million, million, million molecules of glucose in a sugar cube.

explanation:

HAHA d ko alam kung tama yan

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oksian1 [2.3K]

Answer:

The new equilibrium total pressure will be  increased to one-half to initial total pressure.

Explanation:

From the information given :

The equation of the reaction can be represented as;

2SO_{2(g)}+O_{2(g)} \to2SO_{3(g)}

From above equation:

2 moles of sulphur dioxide reacts with 1 mole of oxygen  (i.e 2 moles +1 mole  =3 moles ) to give 2 moles of sulphur trioxide

So; suppose the volume of this system is compressed to one-half its initial volume and then equilibrium is reestablished.

So if this process takes place ; the equilibrium will definitely shift to the side with fewer moles , thus the equilibrium will shift to the right. As such; there is increase in pressure.

Let the total pressure at the initial equilibrium be P_1

and the total pressure at the final equilibrium be P_2

According to Boyle's Law; Boyle's Law states that the pressure of a fixed mass of gas is inversely proportional to the volume, provided the temperature remains constant.

Thus;

P ∝  1/V

P = K/V

PV = K

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So;

PV = constant

Hence;

P_1V_1 = P_2V_2

From the foregoing; since the volume is decreased to one- half to initial Volume; then ,

V_2 =  \dfrac{V_1}{\dfrac{3}{2}} ----- (1)

also;

Thus ;

P_1V_1 = P_2(  \dfrac{V_1}{\frac{3}{2}})

P_1V_1 = P_2 * 2  \dfrac{V_1}{3}

3 P_1 V_1 = 2 P_2 V_1

Dividing both sides by V_1

3P_1 = 2P_2

P_2 =P_1 \dfrac{3}{2}  ----- (2)

From ;

P_1V_1 = P_2V_2

P_2 V_2 = P_1 * \dfrac{3}{2}* \dfrac{V_1}{\frac{3}{2}}

P_2 V_2 = P_1 * \dfrac{3}{2}*   \dfrac{2 }{3}}*V_1

P_2 V_2 = P_1 V_1

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Find the average atomic mass of neon, given the atomic masses and relative abundance of its three isotopes.
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6 0
3 years ago
Which law represents a balanced chemical equation?​
Montano1993 [528]

Answer:

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8 0
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\The specific heat of aluminum is 0.21 cal g°C . How much heat is released when a 10 gram piece of aluminum foil is taken out of
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<u>Answer: </u>The amount of heat released is 84 calories.

<u>Explanation: </u>

The equation used to calculate the amount of heat released or absorbed, we use the equation:

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where,

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Putting values in above equation, we get:

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8 0
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