Answer:
d = 6
Step-by-step explanation:
The nth term of an arithmetic sequence is
= a₁ + (n - 1)d
where a₁ is the first term and d the common difference
Given a₄ = 23 and a₁₁ = 65 , then
a₁ + 3d = 23 → (1)
a₁ + 10d = 65 → (2)
Subtract (1) from (2) term by term to eliminate a₁
10d - 3d = 65 - 23
7d = 42 ( divide both sides by 7 )
d = 6
If you're simplifying, you would get -258 I believe.
<h3>Given</h3>
- arc AB of circle O is 1/4 of the circumference
- radius of circle O is 5
- pi is 3.14
<h3>Find</h3>
<h3>Solution</h3>
Since arc AB is 1/4 of the circumference, the central angle AOB will be 1/4 of a circle, so π/2 in radians. The area of a sector is given by
... A = (1/2)r²·θ
where θ is the central angle in radians and r is the radus.
The area is ...
... A = (1/2)·5²·π/2 = 25π/4
... A ≈ 19.625
The area of the sector is about 19.63 square units.
Answer:
5x + (- 1)
Step-by-step explanation:
So the terms are 2x, -5, 3x, and +4.
2x and 3x have x in common so they can be combined to create 5x.
-5 and +4 don't have variables, so they are also common and can be combined to make -1.
Plug in 5 for t, while ignoring the +75.
Therefore, the anchor drops 12 m. every 5 seconds
