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Ira Lisetskai [31]
3 years ago
7

What is the relationship between mass gravity and weight?

Physics
1 answer:
Basile [38]3 years ago
7 0
Fg=m•g || IE: Weight = mass x gravity
Therefore, the relationship are as follows:
mass and gravity are inversely proportional 
mass and weight are directly proportional
weight and gravity are directly proportional 
You might be interested in
The planet Mars has much less gravitational force that Earth. What would happen if you went to Mars?
vovangra [49]

gravitational force of planet exerted on its object near the surface is known as weight

so here we know that gravitational force of mars is much less than the gravitational force of Earth

So on the surface of mars the Weight of objects must be much less than the weight of object on surface of Earth

so here correct answer must be

<em>D. Your weight would decrease.</em>

6 0
3 years ago
Name two kinds of longitudinal waves and explain how you know they are longitudinal.
dezoksy [38]
A transverse wave and a longitudinal wave.

Transverse:wave particles move at medium speed in perpendicular to the direction that the waves move

Longitudinal:wave particles move at medium speed in parallel to the direction that the wave moves

Hope this helps ^-^
8 0
3 years ago
1. What happens to particle spacing when temperature increase, What we call this process?
enot [183]

Answer:

Particle spacing increases and it's called evaporating

5 0
3 years ago
How much heat is needed to raise the temperature of 5g of water by 20oC?
Ratling [72]
Required Heat = Q

Q = Mass * specific heat of water * change in temp.

Q = 5g * 1g/cal*degC * 20degC

Q = 100 cal of heat is required

To convert calories to Joules,
1 cal = 4.184 Joules

100cal = 418.4 J of heat is needed
5 0
3 years ago
An electric dipole is formed from two charges, ±q, spaced 0.800 cm apart. The dipole is at the origin, oriented along the y-axis
Simora [160]

Answer: q = 2.781e-9C = 2.781nC

E=200C

Explanation:

E = Qd/(2πEor^3)

Where

E=Electric field intensity

Q=Charge

d=distance between the dipole=0.008m

Eo=permitivitty

400 N/C = Q(0.80e-2 m)/(2πε*(10e-2 m)^3)

Q= (400* 2* 3.142 * 8.85 x 10-12 * 0.1^3)/0.008

q = 2.781e-9C = 2.781nC

b)

Though the dipole are two separate charges. And since the point is on the x-axis, the electric field strengths are equivalent. The magnitude of the vector sum is:

E = kq*2sin θ/r^2

= 2(8.99e9 N*m^2/C^2)(2.781e-9 C)*sin(arctan(.4/10))/(10e-2 m)^2

= 2(8.99e9) * (2.781e-9) * sin(2.290)/(10e-2 m)^2

=200 C

3 0
3 years ago
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