1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
solniwko [45]
2 years ago
12

A sphere of radius R = 0.295 m and uniform charge density -151 nC/m^3 lies at the center of a spherical, conducting shell of inn

er and outer radii 3.50 R and 4.00 R , respectively. If the conducting shell carries a total charge of Q = 66.7nC , find the magnitude of the electric field at the at the following radial distances from the center of the charge distribution.
a. 0.760R
b. 3.90R
c. 2.80R
d. 7.30R
Physics
1 answer:
cupoosta [38]2 years ago
6 0

Answer:

a) -1.27*10³ N/C b) 0 c) -0.21*10³ N/C d) 0.1*10³ N/C

Explanation:

a) r = 0.76R

As this distance is inside the sphere, we need to know how much charge is enclosed within this distance for the center, as follows:

Q = ρ*V(r) = ρ*\frac{4}{3} *\pi *r^{3}

where r = 0.760* R = 0.760* 0.295 m = 0.224 m, and ρ = -151 nC/m³

Q = -151e-9 *\frac{4}{3} *\pi *0.224m^{3} = -7.11e-9 C

Applying Gauss' Law to a spherical gaussian surface of r= 0.76R, as the electric field is radial, and directed inward, we can write the following equation:

E*A = Q/ε₀, where Q= -7.11 nC, A= 4*π*(0.76R)² and ε₀ =8.85*10⁻¹² C²/N*m²

We can solve for E, as follows:

E = \frac{1}{4*\pi*8.85e-12C2/N*m2 } *\frac{-7.11e-9C}{(0.76*0.295m)^{2}} =-1.27e3 N/C

⇒ E = -1.27*10³ N/C

b) r= 3.90 R

As this distance falls inside the conducting shell, and no electric field can exist within a conductor in electrostatic condition, E=0

c) r = 2.8 R

As this distance falls between the sphere and the inner radius of the shell, we can calculate the electric field, applying Gauss' law to a gaussian surface of radius equal to r= 2.80 R.

First we need to find the total charge of the sphere, as follows:

Q = ρ*V =

Q = -151e-9 *\frac{4}{3} *\pi *0.295m^{3} = -16.2e-9 C

In the same way that for a) we can write the following expression:

E*A = Q/ε₀, where Q= -16.2 nC, A= 4*π*(2.8R)² and ε₀ =8.85*10⁻¹² C²/N*m²

We can solve for E, as follows:

E = \frac{1}{4*\pi*8.85e-12C2/N*m2 } *\frac{-16.2e-9C}{(2.8*0.295m)^{2}} =-0.21e3 N/C

⇒ E = -0.21*10³ N/C

d) r= 7.30 R

In order to find the electric field at this distance, which falls beyond the outer radius of the shell, we need to find the total charge on the outer surface.

As the sphere has a charge of -16.2 nC, and the total charge of the conducting shell is 66.7nC, in order to make E=0 inside the shell, the total charge enclosed by a gaussian surface with a radius larger than the inner radius of the shell and shorter than the outer one, must be zero, which means that a charge of +16.2 nC must be distributed on the inner surface of the shell.

This leaves an excess charge on the outer surface of the shell as follows:

Qsh = 66.7 nC - 16.2 nC = 50.5 nC

Now, we can repeat the same process than for a) and c) as follows:

E*A = Q/ε₀, where Q= 50.5 nC, A= 4*π*(7.3R)² and ε₀ =8.85*10⁻¹² C²/N*m²

We can solve for E, as follows:

E = \frac{1}{4*\pi*8.85e-12C2/N*m2 } *\frac{50.5e-9C}{(7.3*0.295m)^{2}} =0.1e3 N/C

⇒ E = 0.1*10⁻³ N/C

You might be interested in
Sally and Juan’s science teacher has directed the class to build a paper airplane. The challenge is to build an airplane that fl
devlian [24]
Evaluating a solution
8 0
2 years ago
Read 2 more answers
HELP PLS MARKING BRANLIST 100 Pts TAKING TEST RN
vredina [299]

Answer:

0.5 m/s2

Explanation:

accelration formula : final velocty - starting velocity divided by time

5 0
2 years ago
I need help with question #8 please!!
otez555 [7]

Answer: 3.1158

Explanation: THERE

3 0
2 years ago
A violin string that is 50.0 cm long has a fundamental frequency of 440 Hz. What is the
amid [387]
For a standing wave on a string, the wavelength is equal to twice the length of the string:
\lambda=2 L
In our problem, L=50.0 cm=0.50 m, therefore the wavelength of the wave is
\lambda = 2 \cdot 0.50 m = 1.00 m

And the speed of the wave is given by the product between the frequency and the wavelength of the wave:
v=\lambda f = (1.00 m)(440 Hz)=440 m/s
5 0
3 years ago
Read 2 more answers
Which formula describes Newton’s second law of motion?
Allushta [10]
Newton's second law of motion pertains to the behavior of objects for which all existing forces are not balanced. The second law states that the acceleration of an object is dependent upon two variables - the net force acting upon the object and the mass of the object. The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.

6 0
3 years ago
Read 2 more answers
Other questions:
  • How do you find Net Force?
    15·2 answers
  • A flowerpot falls off a balcony 85m above the street how long does it take to hit the ground
    6·2 answers
  • Winston stands on the edge of a building's flat roof, 12 m above the ground, and throws a 147.0-g baseball straight down. the ba
    6·1 answer
  • Each ball has a negligible size and a mass of 11.5 kg and is attached to the end of a rod whose mass may be neglected. The rod i
    8·1 answer
  • Match the correct term with the definition
    10·2 answers
  • A 2.1 kg block is dropped from rest from a height of 5.5 m above the top of the spring. When the block is momentarily at rest, t
    8·2 answers
  • Suppose a cyclist travels 15 kilometers during the first hour. Then the cyclist travels 33 kilometers during the next 2 hours. W
    8·1 answer
  • Earth’s gravity keeps the moon in orbit by pulling on it.
    14·2 answers
  • WILL MARK BRAINLIST IIF U GIVE ME CORRECT ANSWERS
    15·2 answers
  • Which type of energy resource can be replaced in a short amount of time? 15 Points
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!