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saul85 [17]
3 years ago
5

What Molecules can be found in the interstellar medium? A. Water, Carbon dioxide, and Hydrogen. B. Oxygen, Nitrogen and ammonia.

C. Nitrogen, Carbon dioxide and oxygen. D. hydrogen, Helium and Methane.
Physics
1 answer:
Masteriza [31]3 years ago
3 0
The interstellar medium is the matter as well as the radiations that are found in the galaxies occupying the spaces between the star systems.
Interstellar medium is mainly composed of hydrogen that is followed by helium and trace amounts of nitrogen, oxygen and carbon (considered traces when compared to amount of hydrogen).

Therefor, the right choice is:
<span>A. Water, Carbon dioxide, and Hydrogen</span>
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A champion athlete can produce one horsepower (746 W) for a short period of time. The number of 16-cm-high steps a 70-kg athlete
erastovalidia [21]

Answer:

407 steps

Explanation:

From the question,

P = mgh/t........... Equation 1

Where P = power, m = mass, g = acceleration due to gravity, h = height, t = time.

Make h the subject of the equation

h = Pt/mg............. Equation 2

Given: P = 746 W, t = 1 minute = 60 seconds, m = 70 kg.

Constant: g = 9.8 m/s²

Substitute into equation 2

h = 746(60)/(70×9.8)

h = 44760/686

h = 65.25 m

h = 6525 cm

number of steps = 6525/16

number of steps = 407 steps

6 0
3 years ago
9ma electric current is flowing through a conducting wire , then the number of electron passing through it in 3 min is
Leviafan [203]

Answer:

1.0125 x 10^19

Explanation:

current flowing through conductive wire= 9mA = 9 x 10^ -3 A

charge passing per 3 min

Q = It

= 9 x 10^ -3 x (3 x 60)

= 1.620 C

no of electrons in charge

Q = ne

1.620 = n x 1.6 x 10 ^ -19

n. = 1.0125 x 10 ^19

4 0
3 years ago
A hungry 173173 kg lion running northward at 82.782.7 km/hr attacks and holds onto a 36.236.2 kg Thomson's gazelle running eastw
Galina-37 [17]

Answer:

the final speed after attack is 69.09 km/h

Explanation:

lion weight = 173 kg

running northward at 82.7 km/hr

weight of gazelle = 36.2 kg

running eastward at 57.4 km/hr

using momentum conservation along north direction

(173) × (82.7)  = (173 + 36.2 ) × vₙ

vₙ = 68.38 km/h

using momentum conservation along east direction

36.2 × 57.4 =  (173 + 36.2 ) × vₓ

vₓ = 9.93 km/h

v = \sqrt{v^2_n+v^2_x} \\v = \sqrt{68.38^2+9.93^2}\\v=69.09 km/h

hence the final speed after attack is 69.09 km/h

8 0
3 years ago
Which statement about the acceleration of an object is correct?
Step2247 [10]

Answer:

a. The acceleration of an object is directly proportional to the net external force acting on the object and inversely proportional to the mass of the object.

Explanation:

Newton's Second Law of Motion states that the acceleration of a physical object is directly proportional to the net force acting on the physical object and inversely proportional to its mass.

Mathematically, it is given by the formula;

Acceleration = force/mass

Hence, the statement about the acceleration of an object which is correct is that the acceleration of an object is directly proportional to the net external force acting on the object and inversely proportional to the mass of the object.

3 0
3 years ago
Two charged particles are moving with equal velocities of 4.00 m/s in the +x-direction. At one instant of time the first particl
olganol [36]

Answer:

Explanation:

Electric  force between two particles

= ( 9x10⁹x7.4 x 10⁻⁶ x 3.2 x 10⁻⁶ )/  (3.2 x 10⁻²)² ( Distance between particles is 1.6 +1.6 = 3.2 cm . )

= 20.81 x 10 = 208.1 N

1 ) Magnetic field due to movement of second charge

= \frac{\mu_0}{4\pi} \frac{qv}{r^2  }

= 10⁻⁷ x 3.2 x 10⁻⁶ x 4 / (3.2 x 10⁻²)²

B = 1.25 x 10⁻⁹ T.

Due to this magnetic field , there is a force called magnetic force on first particle which will be expressed as follows

Force = Bqv

= 1.25 x 10⁻⁹ x 7.4 x 10⁻⁶ x 4

37 x 10⁻¹⁵ N

2 ) For magnetic force to be equal to electric force let velocity o particles be V

Then magnetic field due to second charge

= 10⁻⁷ x 3.2 x 10⁻⁶ x v / (3.2 x 10⁻²)²

= .3125 v x  10⁻⁹

Magnetic force on first charge

Bqv

=  .3125 v x  10⁻⁹  x 7.4 x 10⁻⁶ x v

2.3125 x 10⁻¹⁵ v²

magnetic force = electric force

2.3125 x 10⁻¹⁵ v² = 208.1

v² = 90 x 10¹⁵

v² = 900 x 10¹⁴

v = 30 x 10⁷ m /s

6 0
3 years ago
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