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saul85 [17]
3 years ago
5

What Molecules can be found in the interstellar medium? A. Water, Carbon dioxide, and Hydrogen. B. Oxygen, Nitrogen and ammonia.

C. Nitrogen, Carbon dioxide and oxygen. D. hydrogen, Helium and Methane.
Physics
1 answer:
Masteriza [31]3 years ago
3 0
The interstellar medium is the matter as well as the radiations that are found in the galaxies occupying the spaces between the star systems.
Interstellar medium is mainly composed of hydrogen that is followed by helium and trace amounts of nitrogen, oxygen and carbon (considered traces when compared to amount of hydrogen).

Therefor, the right choice is:
<span>A. Water, Carbon dioxide, and Hydrogen</span>
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hot-air balloon is ascending at the rate of 14 m/s and is 84 m above the ground when a package is dropped over the side. (a) How
timurjin [86]

Answer:

a) t = 4.14 s

b) Speed with which it hits the ground = 40.58 m/s

Explanation:

Using the equations of motion,

g = 9.8 m/s², y = H = 84 m,

Initial velocity, u = 0 m/s,

final velocity, v = ?

Total Time of fall, t = ?

a) y = ut + gt²/2

84 = 0 + 9.8t²/2

4.9t² = 84

t² = 84/4.9

t = 4.14 s

b) v = u + gt

v = 0 + (9.8 × 4.14)

v = 40.58 m/s

4 0
3 years ago
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What is the slit spacing of a diffraction necessary for a 600 nm light to have a first order principal maximum at 25.0°?
Sauron [17]

Explanation:

Given that,

Wavelength of light, \lambda=600\ nm=6\times 10^{-7}\ m

Angle, \theta=25^{\circ}

We need to find the slit spacing for diffraction. For a diffraction, the first order principal maximum is given by :

d\sin\theta=n\lambda

n is 1 here

d is slit spacing

d=\dfrac{\lambda}{\sin\theta}\\\\d=\dfrac{6\times 10^{-7}}{\sin(25)}\\\\d=1.41\times 10^{-6}\ m\\\\d=1.41\ \mu m

So, the slit spacing is 1.41\ \mu m.

6 0
3 years ago
Help help help help help help help help help
Stells [14]
Yes yes yes yes yes yes yes yes
4 0
3 years ago
Read 2 more answers
PHYSICS! I AM TIMED!
Lana71 [14]
28J because mechanical energy is the sum of the potential energy and kinetic energy
8 0
3 years ago
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HELP ;
mestny [16]

Answer:

The frequency would double.

Explanation:

Given:

Speed of wave (v) = constant.

Frequency of wave initially (f₁) = 2 Hz

Initial wavelength of the wave (λ₁) = 1 m

Final wavelength of the wave (λ₂) = 0.5 m

Final frequency of the wave (f₂) = ?

We know that the product of wavelength and frequency of the wave is equal to the speed of the wave.

Therefore, framing in equation form, we have:

Wavelength × Frequency = Speed

\lambda\times f=v

It is given that speed of the wave remains the same. So, the product must always be a constant.

Therefore,

\lambda\times f=constant\ or\ \\\lambda_1\times f_1=\lambda_2\times f_2

Now, plug in the given values and solve for 'f₂'. This gives,

1\times 2=0.5\times f_2\\\\f_2=\frac{2}{0.5}=4\ Hz

Therefore, the final frequency is 4 Hz which is double of the initial frequency.

f₂ = 2f₁ = 2 × 2 = 4 Hz

So, the second option is correct.

7 0
3 years ago
Read 2 more answers
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