Answer:
40.3 for the unit that represents the minimum amount of magnesium oxide I beilieve.
Explanation:
Magnesium atoms are heavier than oxygen atoms, so we expect more than 50% of magnesium in the weight composition. Taking just one atom of Mg and one atom of O you will get a mass of 16.0 + 24.3 = 40.3.
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Answer:
1.d = 2.70 g/mL
2.d = 13.6 g/mL
4.d = 1896 g / 212.52 cm3 = 8.9 g/cm3
Explanation:If this helped subscribe to Amiredagoat Yt
I believe it is c because cohesion holds hydrogen bonds together to create surface tension on water
Answer:
0.12 g/L
Explanation:
We first calculate its molar mass M = solubility at STP × molar volume = 0.14 g/L × 22.4 L/mol = 3.14 g/mol
Using the ideal gas law, PV = mRT/M where P = pressure at STP = pressure at 50°C = 1 atm, V = volume of gas, m = mass of gas, R = molar gas constant = 0.082 atm L/mol-K, T = temperature of gas = 50°C = 273 + 50 = 323 K and M =molar mass of gas = 3.14 g/mol
So, PM/RT = m/V = solubility of gas at 50°C
So, PM/RT = 1 atm × 3.14 g/mol/(0.082 atm L/mol-K × 323 K)
= 3.14 atm g/mol ÷ 26.486 atm L/mol
= 0.119 g/L
≅ 0.12 g/L
