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marshall27 [118]
4 years ago
10

Sexual reproduction helps to increase

Chemistry
1 answer:
zalisa [80]4 years ago
3 0
The answer to the question is A
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Please can I have help on question e as I’m really stuck.I promise I’ll give out brainiest
Natasha_Volkova [10]

The relative atomic mass of element A : 6.075 u

<h3>Further explanation </h3>

The elements in nature have several types of isotopes

Isotopes are atoms whose no-atom has the same number of protons while still having a different number of neutrons.

So Isotopes are elements that have the same Atomic Number (Proton)

Atomic mass is the average atomic mass of all its isotopes

Mass atom X = mass isotope 1 . % + mass isotope 2.% ...

Element A

mass number of isotope 1 = 6 , percent : 92.5%

mass number of isotope 2 = 7, percent : 7.5

Relative atomic mass of element A

\tt = 92.5\%\times 6+7.5\%\times 7\\\\=5.55+0.525=6.075~u

5 0
3 years ago
True or false : rust formation is not a chemical property of iron
Maurinko [17]

Answer:

false and rust is hydrated iron oxide so it is a form off iron

4 0
2 years ago
What is the freezing point of silver?​
rosijanka [135]

Answer:

1,763°F

Explanation:

I really cant explain it is a little complicated but there is the answer hope it helped you a lot

6 0
3 years ago
Read 2 more answers
Hey so i dont get this help please​
Leya [2.2K]

Answer:

ta da

Explanation:

8 0
3 years ago
Determine the ph of a 0.188 m nh3 solution at 25°c. the kb of nh3 is 1.76 × 10-5.
Ber [7]
When NH3 is dissolved in water, it dissociates  partially producing NH4+ ions and OH- ions. It has an equation:
NH3 + H2O → NH4+ + OH- 

<span>We use the Kb expression to determine the [OH-] concentration,
</span>
<span>Kb = [NH4+] [OH-] /* [NH3] </span>

We can write NH4+ as OH- since they are of equal ratio. 
<span>(1.76*10^-5) = [OH-]² / 0.188 
</span><span>[OH-]² = 3.3088*10^-6 </span>
<span>[OH-] = 1.819*10^-3 </span>

We calculate for H+ concentration as follows:

<span>[H+] [OH-] = 10^-14 </span>
<span>[H+] = 10^-14 / [OH-] </span>
<span>[H+] = 10^-14 / (1.819*10^-3) </span>
<span>[H+] = 5.50*10^-12 </span>

<span>pH = -log [H+] </span>
<span>pH = -log (5.5*10^-12) </span>
<span>pH = 11.26</span>
4 0
3 years ago
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