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maria [59]
2 years ago
15

If an asset declines in value from $5000 to $3500 over nine years, what is the mean annual growth rate in the asset's value over

these nine years? Round your answer to two decimal places.
Mathematics
1 answer:
babymother [125]2 years ago
5 0
<span>If an asset declines in value from $5000 to $3500 over nine years, then the mean annual growth rate in the asset's value over these nine years to two decimal places is given by:

Mean\, growth\, rate= \frac{3500-5000}{9} = \frac{-1500}{9} =-\$166.67</span>
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20)
Nataly [62]

Answer:

babysitting = $9

working at coffeehouse = $12

x = hours for babysitting

y = hours at coffeehouse

minimum = ≥

9x + 12y ≥ 240

Step-by-step explanation:

just a short note on which symbol you should use when you see these words in inequality questions:

i) use ≥

-more than or equal to

-not less than

-at least

-minimum

ii) use >

-more than

-greater than

iii) use ≤

-less than or equal to

-not more than

-at most

-maximum

iv) use <

-less than

7 0
2 years ago
78 times 56 plz help me
rewona [7]
Your answer is 4,368
7 0
2 years ago
Read 2 more answers
According to a survey of college students, the use of social media varies widely according to age. Based on the survey, what is
Yanka [14]

Answer:

C. 65

Step-by-step explanation:

The table which shows the results of the survey are attached below.

From the table:

  • Total Number of non-social media users = 71
  • Number of non-social media user aged 28 and up = 46

Therefore, the probability that a non-social media user is an older student aged 28 and up

=\dfrac{\text{ Number of non-social media user aged 28 and up}}{\text{ Total Number of non-social media users}}\\\\=\dfrac{46}{71} \times 100\\\\=64.7\\\\\approx 65\%

The probability that a non-social media user is an older student aged 28 and up is 65%.

<u>The correct option is C. </u>

4 0
3 years ago
BRAINLIEST ✨
inna [77]

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, or</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, or</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, or</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6</em>

<em>Solution: T2 = a+d, T4 =a+3d. T7 = a+6d.In the GP: (a+d)(a+6d) = (a+3d)^2, ora^2+7ad+6d^2 = a^2+6ad+9d^2, orad = 3d^2, ora = 3d.a = 2, d = 2/3.The common ratio of the GP is 3/2. Answer.Check: (2 + 2/3), (2 + 3*2/3), (2 + 6*2/3)= 8/3, 4, 6Common ratio: 4/(8/3) = 3/2 same as 6/4 = 3/2. Correct.</em>

Step-by-step explanation:

Am I right? just commet if I'm wrong

then <em>TANKYOU>^_^<!</em>

7 0
2 years ago
Determine the missing y value if the slope of a line is 4/3 and the line passes through the points (5,x) and (2,-3)
Simora [160]

Answer:

x = -7

Step-by-step explanation:

Given parameters:

Slope of the line = \frac{4}{3}

 Coordinates =  (5,x) and (2,-3)

Unknown:

X= ?

Solution:

  To find slope, use the expression below;

   Slope  = \frac{y_{2} - y_{1}  }{x_{2} - x_{1} }

y₂ = -3  y₁ = x

x₂ = 2   x₁ = 5

   \frac{4}{3}  = \frac{-3 - x}{2 - 5}

           3(-3-x) = 4(-3)

            -9 -3x = 12

                -3x = 21

                  x = -7

8 0
3 years ago
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