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Natalka [10]
3 years ago
12

The Buddhist teaching of ______________ asserts that everything is in a perpetual state of flux (always changing), yet we imagin

e that some things are constant.
Physics
1 answer:
dezoksy [38]3 years ago
5 0

Answer:

<u>B. impermanence</u>

Explanation:

One of the many popular religions is Buddhism. Those who believe in it's teachings are called Buddhist.  The impermanence teaching is a Buddhist teaching that sserts that everything is in a perpetual state of flux (always changing).

<em>Impermanence in the sense of nothing being permanent </em>but always changing.

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If it attractive it has opposite pole and if it repulsive it has same pole
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6. Explain the difference between a neutral atom and an ion?
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Answer:

a neutral atom doesn't have a charge and an ion does.

Explanation:

When atoms bond they can gain or lose electrons which gives them a charge.

anion = negatively charged ion

cation = positively charged ion

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What is the name for the bunched up region of<br> air particles in the sound wave?
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Read 2 more answers
A car accelerates for 10 seconds. During this time, the angular
bagirrra123 [75]

Answer:

the angular acceleration of the car is 1.5 rad/s²

Explanation:

Given;

initial angular velocity, \omega_i = 10 rad/s

final angular velocity, \omega_f = 25 rad/s

time of motion, t = 10 s

The angular acceleration of the car is calculated as follows;

a_r = \frac{\omega_f - \omega_i }{t} \\\\a_r = \frac{25-10}{10} = 1.5 \ rad/s^2

Therefore, the angular acceleration of the car is 1.5 rad/s²

4 0
3 years ago
a ball is thrown inclined in to the air with a initial velocity of u. if it reaches the maximum height in 6 seconds , find the r
olga55 [171]

Answer:

11:1

Explanation:

At constant acceleration, an object's position is:

y = y₀ + v₀ t + ½ at²

Given y₀ = 0, v₀ = u, and a = -g:

y = u t − ½g t²

After 6 seconds, the ball reaches the maximum height (v = 0).

v = at + v₀

0 = (-g)(6) + u

u = 6g

Substituting:

y = 6g t − ½g t²

The displacement between t=0 and t=1 is:

Δy = [ 6g (1) − ½g (1)² ] − [ 6g (0) − ½g (0)² ]

Δy = 6g − ½g

Δy = 5½g

The displacement between t=6 and t=7 is:

Δy = [ 6g (7) − ½g (7)² ] − [ 6g (6) − ½g (6)² ]

Δy = (42g − 24½g) − (36g − 18g)

Δy = 17½g − 18g

Δy = -½g

So the ratio of the distances traveled is:

(5½g) / (½g)

11 / 1

The ratio is 11:1.

8 0
4 years ago
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