<h2>
Answer: D. 70.0 J</h2>
Explanation:
3.00 m + 4.00 m = 7.00 m x 10.0 N = 70.0 J
Knowing the force and distance allows you to calculate the work done.
Then, if you know the TIME, you can calculate the power.
Answer:
The magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J
Explanation:
Given;
radius of the circular loop of wire = 0.5 m
current in circular loop of wire = 2 A
strength of magnetic field in the wire = 0.3 T
τ = μ x Bsinθ
where;
τ is the magnitude of the magnetic torque
μ is the dipole moment of the magnetic field
θ is the inclination angle, for a plane area perpendicular to the magnetic field, θ = 90
μ = IA
where;
I is current in circular loop of wire
A is area of the circular loop = πr² = π(0.5)² = 0.7855 m²
μ = 2 x 0.7885 = 1.571 A.m²
τ = μ x Bsinθ = 1.571 x 0.3 sin(90)
τ = 0.4713 J
Therefore, the magnitude of the magnetic torque on the loop when the plane of its area is perpendicular to the magnetic field is 0.4713 J
Compound and events are pure substance
As per Newton's law rate of change in momentum is net force
so we can write it as
now we know that
from above equation
so he will experience 900 N force in above case
