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kumpel [21]
3 years ago
8

Write the equation of the line perpendicular to 3x+2y=-8 that passes through (3,1). Write you answer in slope-intercept form. Sh

ow ALL your work!
Mathematics
1 answer:
Verdich [7]3 years ago
3 0

Answer:

y = (2/3)x - 1,  slope-intercept form

Step-by-step explanation:

3x + 2y = - 8

2y = -3x - 8

y = (-3/2) x - 4

Slope of this line is -3/2.

For the perpendicular line slope is 2/3.

Point - slope form is

(y - y1) = m(x - x1)

Point is (3,1). Slope m = 2/3.

y - 1 = (2/3)*(x - 3)

y - 1 = (2/3)x - 2

y = (2/3)x - 1,  slope-intercept form

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6 0
3 years ago
Someone help me with this
skad [1K]

Answer:

m∠ABC = 74

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3 years ago
Find the values of m and b that make the following function differentiable.
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The derivative of f(x) at x=3 is 2x=6 approaching from the left side (apply power rule to y=x^2). The derivative of f(x) at x=3 is m approaching from the right side. In order for the function to be differentiable, the limit of derivative at x=3 must be the same approaching from both sides, so m=6. Then, x^2=mx+b at x=3, plug in m=6, 9=18+b, so b=-9.
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Answer:

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