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yuradex [85]
4 years ago
6

A red car with a mass of 3.0 kg traveling at 8 m/s collided with a blue car with a mass of 2.0 kg, which is at rest. The velocit

y of the blue car after the elastic collision is 9.6 m/s. What is the velocity of the red car?
Physics
1 answer:
anygoal [31]4 years ago
8 0

Answer:

460.8

Explanation:

just combine like terms

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3. A cart with mass of 30 kg is traveling with a velocity of 4.0 m/s. The
MaRussiya [10]

Answer:

39 m/s

Explanation:

8 0
3 years ago
Read 2 more answers
What does it mean to say that some elements are reactive and form ions easily whereas others do not?
butalik [34]

Answer:

Some elements are reactive because the outermost energy levels of their atoms are only partially filled. Therefore, these atoms can easily gain or lose electrons to form ions. The atoms of nonreactive elements have filled outermost energy levels

Explanation:

hope this answers your ?

4 0
2 years ago
The base of a pyramid covers an area of 13.0 acres (1 acre = 43,560 ft2) and has a height of 481 ft. If the volume of a pyramid
Allisa [31]
V = 1/3 Bh v = 1/3 (13 ac)(43560ft^2/ac)(481ft) v = 90793560 ft^3 * 0.3048m/ft * 0.3048m/ft * 0.3048m/ft = 2570987m^3
3 0
3 years ago
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Explain how thermal energy (temperature) affects chemical changes.
Monica [59]
If bonds are broken, the energy is released, and if bonds are formed, energy is absorbed. During conversions from chemical energy to thermal energy, the energy stored in the chemical bonds are released and this energy causes surrounding molecules to move faster thus increasing the thermal energy of a substance.
8 0
3 years ago
You can use any coordinate system you like in order to solve a projectile motion problem. To demonstrate the truth of this state
posledela

Answer:

a)  y₂ = 49.1 m ,    t = 1.02 s , b)   y = 49.1 m , t= 1.02 s

Explanation:

a) We will solve this problem with the missile launch kinematic equations, to find the maximum height, at this point the vertical speed is zero

            v_{y}² = v_{oy}² - 2 g (y –yo)

The origin of the coordinate system is on the floor and the ball is thrown from a height

           y-yo = v_{oy}² /2 g
            y- 0 = 10.0²/2 9.8
            y - 0 = 5.10 m
            
The height from the ground is the height that rises from the reference system plus the depth of the ground from the reference system
             y₂ = 5.1 + 44
             y₂ = 49.1 m
Let's use the other equation to find the time
              [tex]v_{y} = v_{oy} - g t

              t = v_{oy} / g

              t = 10 / 9.8

              t = 1.02 s

b) the maximum height

            y- 44.0 = v_{y}² / 2 g

            y - 44.0 = 5.1

            y = 5.1 +44.0

            y = 49.1 m

The time is the same because it does not depend on the initial height

              t = 1.02 s

7 0
4 years ago
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