Velocity of vw bug is given as
towards north
velocity of imphala is given as
towards south
now we need to find velocity of imphala relative to bug


so the speed is 101 mpH towards south so correct option is C
Answer:
or 0.07163 T into the page
Explanation:
m = Mass of particle = 10 g
a = Acceleration due to gravity = -9.8j m/s²
v = Velocity of particle = 19i km/s
q = Charge of particle = 72 μC
B = Magnetic field
Here the magnetic and gravitational forces on the particle are applied in the opposite direction so,




The magnetic field is 0.07163 T into the page
Answer:
This represents radiation in ultra-violet region .
Explanation:
Energy of the orbit where n = 3 is given as follows

= -1.511 eV
Energy of the orbit where n = 1 is given as follows

= 13.6 eV
Difference of [tex]E_3 and [tex]E_1 = - 1.511+ 13.6
= 12.089 eV.
The wavelength of light having this energy in nm is given by the expression as follows
Wavelength in nm = 1244 / energy in eV
= 1244 / 12.089
= 102.90 nm
This represents radiation in ultra-violet region .
Answer: according to the Avagadro's law, volume is directly propotional to no of moles: VXn
according to the Charles law, volume is directly propotional to temperatue: VXT
according to the Boyle's law, volume is inversely propotional to P: VX1/P
when we combine them we get:
VXnT1/P
V=knT/P
k= R(universal gas constant)
V=RnT/P
PV=nRT
<span>By algebra, d = [(v_f^2) - (v_i^2)]/2a.
Thus, d = [(0^2)-(15^2)]/(2*-7)
d = [0-(225)]/(-14)
d = 225/14
d = 16.0714 m
With 2 significant figures in the problem, the car travels 16 meters during deceleration.</span>