Answer:
r = 4.21 10⁷ m
Explanation:
Kepler's third law It is an application of Newton's second law where the forces of the gravitational force, obtaining
T² = (
) r³ (1)
in this case the period of the season is
T₁ = 93 min (60 s / 1 min) = 5580 s
r₁ = 410 + 6370 = 6780 km
r₁ = 6.780 10⁶ m
for the satellite
T₂ = 24 h (3600 s / 1h) = 86 400 s
if we substitute in equation 1
T² = K r³
K = T₁²/r₁³
K =
K = 9.99 10⁻¹⁴ s² / m³
we can replace the satellite values
r³ = T² / K
r³ = 86400² / 9.99 10⁻¹⁴
r = ∛(7.4724 10²²)
r = 4.21 10⁷ m
this distance is from the center of the earth
Using the precise speed of light in a vacuum (
![299,792,458 \ \frac{m}{s}](https://tex.z-dn.net/?f=299%2C792%2C458%20%5C%20%5Cfrac%7Bm%7D%7Bs%7D%20)
), and your given distance of
![1.152 * 10^{8} km](https://tex.z-dn.net/?f=1.152%20%2A%2010%5E%7B8%7D%20km)
, we can convert and cancel units to find the answer. The distance in m, using
![\frac{1000 \ m}{1 \ km}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1000%20%5C%20m%7D%7B1%20%5C%20km%7D%20)
, is
![1.152 * 10^{11} m](https://tex.z-dn.net/?f=1.152%20%2A%2010%5E%7B11%7D%20m)
. Next, for the speed of light, we convert from s to min, using
![\frac{1 \ min}{60 \ s}](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%20%5C%20min%7D%7B60%20%5C%20s%7D%20)
, so we divide the speed of light by 60. Finally, dividing the distance between the Sun and Venus by the speed of light in km per min, we find that it is
6.405 min.
Answer:
0.5kg
Explanation:
Given parameters:
Potential energy = 147J
Height = 30m
Unknown:
Mass of the bird = ?
Solution:
Potential energy is the energy due to the position of a body. Now, the expression for finding the potential energy is given as;
P.E = mgH
m is the mass
g is the acceleration due to gravity = 9.8m/s²
H is the height
147 = m x 9.8 x 30
m = 0.5kg