The name of the aldehyde is 4, 7- diethyldecanal (D)
<h3>
What are rules for naming organic compounds?</h3>
The rules for naming organic compounds are;
- Find the longest carbon chain in the compound. ...
- Name the longest carbon chain found
- Figure the ending name
- Then number the carbon atoms
- Name the side groups
- Then put the side groups in alphabetical order.
The longest chain of the structure given is 10 (deca)
It is an alkanal due to the presence of the carbonyl -CHO
There are two side groups (ethyl) at the 4th and 7th carbon atoms which are both the same, CH2CH3 and are named diethyl
Thus, the name of the aldehyde is 4, 7- diethyldecanal
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When the concentration is expressed in molality, it is expressed in moles of solute per kilogram of solvent. Since we are given the mass of the solvent, which is water, we can compute for the moles of solute NaNO3.
0.5 m = x mol NaNO3/0.5 kg water
x = 0.25 mol NaNO3
Since the molar mass of NaNO3 is 85 g/mol, the mass is
0.25 mol * 85 g/mol = 21.25 grams NaNO3 needed
The option that would be appropriate to model nuclear fission is disturbing a drop of water such that it breaks into smaller droplets
Nuclear fission refers to the splitting of a heavy nucleus into lighter nuclei owing to the bombardment of small particle.
The liquid drop model provides the most apt model for describing the concept of nuclear fission. In nuclear fission, the nucleus breaks due to the increase in repulsion between the nuclear charges.
As the size of the nucleus continues to increase, any little disruption will; result in the breaking up of the nucleus into smaller fragment called daughter nuclei.
Hence, the model of disturbing a drop of water such that it breaks into smaller droplets is the most apt description of nuclear fission.
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The temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.
<h3>How to calculate temperature change?</h3>
The temperature change of a calorimeter can be calculated using the following expression:
E = mc∆T
Where;
- E = energy in joules
- m = mass
- c = specific heat capacity = 4.18J/g°C
- ∆T = change in temperature
400 = 10 × 4.18 × ∆T
400 = 41.8∆T
∆T = 400/41.8
∆T = 9.57°C
Therefore, the temperature change if 400 J of energy is added to 10 grams of water is 9.57°C.
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Answer:
During complete oxidation of the fatty acid CH3(CH2)14COOH, eight molecules of acetyl-CoA are produced, and the fatty acid goes through the β-oxidation cycle seven times.
Explanation:
In the β-oxidation of fatty acids, an acetyl-CoA molecule is removed from the fatty acid chain after every β-oxidation cycle that the fatty acid undergo, leaving behind a fatty acyl-CoA molecule shortened by two cabon atoms..
The removal of the acetyl-CoA molecule starts from the carboxyl end and shortens the fatty acid molecule by two carbon units. Successive β-oxidation cycles results in the complete oxidaton of the fatty acid molecle to acetyl -CoA molecules.
The compound CH3(CH2)14COOH, is a 16-carbon saturated fatty acid molecule known as palmitic acid.. It undergoes seven passes through the β-oxidation cycle to yield eight molecules of acetyl-CoA with each cycle yielding an acetyl-CoA molecule and a fatty acyl-CoA shortened by two carbon atoms. Finally, the seventh step yields two acetyl-CoA molecules.
