Answer:

Explanation:
Hello,
Based on the given information, the radius is computed via:

By assuming that the radius of the element is 1.2x10m, nevertheless, that is a pretty much big radius for an atom in meters, maybe a power is missing, but you can modify it by just including it in the aforesaid formula.
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To calculate this you need to interact a sulfate with the copper sulfate therefore when you get a copper sulfate reaction with the oxygen mask level it should create a dance dance revolution of the proxies equaling the new chemical in balance of peace birds hope this
A. neutrons
Isotopes <span>contain equal numbers of protons but different numbers of neutrons in their nuclei.</span>
0.309g
Explanation:
Mass of evaporating dish = 6.251g
Mass of evaporating dish and sample of hydrate = 16.864g
solving for mass of hydrate before heating;
Mass of hydrate =
mass of evaporating dish and sample of hydrate - mass of evaporating dish;
Mass of hydrate before heating = 16.864g - 6.251g = 10.613g
Upon heating ;
Mass of hydrate plus dish = 11.3g
Unknown:
number of moles of water removed from the hydrate = ?
We need to find the mass of water removed from the hydrate;
Mass of hydrate after heating =mass of hydrate plus dish after heating - mass of evaporating dish
mass of hydrate after heating = 11.3g - 6.251g = 5.049g
Mass of water lost = Mass of hydrate before heating - mass of hydrate after heating
= 10.613g - 5.049g
= 5.564g
Number of moles of water = 
number of moles of water = 0.309moles
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Answer:
See explanation
Explanation:
In order to do this, we need to use 3 reagents to get the final product.
The first one, and logic is the halogenation of the alkene. Doing this, with Br2/CCl4, we'll get an alkane with two bromines, one in carbon 2 and the other in carbon 3.
Then, the next step is to eliminate one bromine of the reactant. The best way to do this, is using sodium ethoxide in ethanol. This is because sodium ethoxide is a relatively strong base, and it will promove the product of elimination in major proportions rather than the sustitution product. If we use NaOH is a really strong base, and it will form another product.
When the sodium ethoxide react, it will form a double bond between carbon 1 and 2 (The carbon where one bromine was with the methyl, changes priority and it's now carbon 3).
The final step, is now use acid medium, such H3O+/H2O or H2SO4/H2O. You can use any of them. This will form an carbocation in carbon 2 (it's a secondary carbocation, so it's more stable that in carbon 1), and then, the water molecule will add to this carbon to form the alcohol.
See the attached picture for the mechanism of this.