Answer:
11 pennies and 9 nickels
Step-by-step explanation:
Set up a system of equations where p is the number of pennies and n is the number of nickels:
p + n = 20
0.01p + 0.05n = 0.56
Solve by substitution by rearranging the first equation:
p + n = 20
p = 20 - n
Then, plug this in as p into the second equation, and solve for n:
0.01p + 0.05n = 0.56
0.01(20 - n) + 0.05n = 0.56
0.2 - 0.01n + 0.05n = 0.56
0.2 + 0.04n = 0.56
0.04n = 0.36
n = 9
Then, plug this into the first equation to solve for p:
p + n = 20
p + 9 = 20
p = 11
So, Jayden has 11 pennies and 9 nickels
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