1st,2nd,3rd,4th that is your answer
Answer:
there 3x and 4y hope this makes sense ik on a rush
The zeroes of <span>f(x) = x^5-12x^2+32x can be found by factoring,
</span><span>f(x) = x^5-12x^2+32x=(x-8)(x-4)
By the zero product theorem, (x-8)=0 or (x-4)=0 which means
x=8 or x=4.
So the zeroes of f(x) are S={4,8}</span>
Well done mate you’re correct.
