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2 years ago

Please help with this problem Solve for x 5x+3=18

Mathematics

2 answers:

sergejj [24]2 years ago

8 0

Answer:

Step-by-step explanation:

X equals the unknown number. In order to find the number subtract three from eighteen to get an answer of fifteen

tino4ka555 [31]2 years ago

6 0

X= 3
Cancel 3 out by subtracting it by itself, then subtract 3 from 18 to get 15. Now that you have 5x= 15, just divide 15 by 5x to get x= 3

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The weight of an empty truck is 7860 pounds

HACTEHA [7]

Okay so whats the question?

7 0

3 years ago

From the sum of 4a + b + c and 9a - c subtract the sum of 18a - b - c and 14a - 2b - c

sergiy2304 [10]

1:-

$\\ \rm\Rrightarrow 4a+b+c+9a-c$

$\\ \rm\Rrightarrow 4a+9a+b+c-c$

$\\ \rm\Rrightarrow 13a+b$

2:-

$\\ \rm\Rrightarrow 18a-b-c-(14a-2b-c)$

$\\ \rm\Rrightarrow 18a-b-c-14a+2b+c$

$\\ \rm\Rrightarrow 18a-14a-b+2b-c+c$

$\\ \rm\Rrightarrow 4a+b$

5 0

2 years ago

Read 2 more answers

Please Help. ------------------------------------------------------

Morgarella [4.7K]

Answer:

positive integers less than or equal to 4

Step-by-step explanation:

The number of splits is described by a counting number: 1, 2, 3, ..., so is a positive integer. The description of the plant tells you that the value of x will be a maximum of 4.

The domain is positive integers less than or equal to 4.

8 0

2 years ago

Find dy/dx by implicit differentiation for ysin(y) = xcos(x)

tatyana61 [14]

Answer:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

Step-by-step explanation:

So we have:

$y\sin(y)=x\cos(x)$

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

$\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]$

Let's do each side individually.

Left Side:

We have:

$\frac{d}{dx}[y\sin(y)]$

We can use the product rule:

$(uv)'=u'v+uv'$

So, our derivative is:

$=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]$

We must implicitly differentiate for y. This gives us:

$=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]$

For the sin(y), we need to use the chain rule:

$u(v(x))'=u'(v(x))\cdot v'(x)$

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

$=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})$

Simplify:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}$

And we are done for the right.

Right Side:

We have:

$\frac{d}{dx}[x\cos(x)]$

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

$=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]$

Differentiate:

$=\cos(x)-x\sin(x)$

So, our entire equation is:

$=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)$

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

$\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)$

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

$\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}$

And we're done!

5 0

2 years ago

Plz help plz asap lol HAHAHA plz

NISA [10]

Answer:

Mario ate 27.27% of her cookies

8 0

3 years ago