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Vera_Pavlovna [14]
2 years ago
7

How do scientists determine locations for drilling for natural gas? Where are many natural gas drill sites located? (Site 2)

Chemistry
1 answer:
Alchen [17]2 years ago
5 0

Explanation:

By<em> </em><em>drilling</em><em> </em><em>several</em><em> </em><em>cores</em><em> </em><em>miles</em><em> </em><em>ap</em><em>art</em><em> </em><em>,</em><em> </em><em>geologist</em><em> </em><em>c</em><em>a</em><em>n</em><em> </em><em>correlate</em><em> </em><em>the</em><em> </em><em>rock</em><em> </em><em>units</em><em> </em><em>and</em><em> </em><em>create</em><em> </em><em>an</em><em> </em><em>image</em><em> </em><em> </em><em>what</em><em> </em><em>exists</em><em> </em><em>and</em><em> </em><em>where</em><em> </em><em>below</em><em> </em><em>the</em><em> </em><em>surfac</em><em>e</em><em>.</em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em>

<em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em> </em><em>Combining</em><em> </em><em>this</em><em> </em><em>information</em><em> </em><em>with</em><em> </em><em>rocks</em><em> </em><em>exposed</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>surface</em><em> </em><em>,</em><em> </em><em>which</em><em> </em><em>can</em><em> </em><em>gives</em><em> </em><em>clues</em><em> </em><em>about</em><em> </em><em>rock</em><em> </em><em>orientation</em><em> </em><em>below</em><em>,</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>a</em><em> </em><em>powerful</em><em> </em><em>tool</em><em> </em><em>to</em><em> </em><em>locating</em><em> </em><em>oil</em><em> </em><em>and</em><em> </em><em>gas</em><em> </em><em>.</em>

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What volume of an hcl solution with a ph of 1.3 can be neutralized by one dose of milk of magnesia?
kvv77 [185]

274 mL H3 O+ and fully neutralized

It will take one teaspoon of Mg(OH)2 to completely neutralize 2.00×10^2mL  of H3O+.

<h3>What is the purpose of milk of magnesia?</h3>
  • For a brief period of time, this medicine is used to relieve sporadic constipation.
  • It is an osmotic laxative, which means that it works by drawing water into the intestines, which aids in causing bowel movement.
<h3>What dosage of milk of magnesia is recommended for constipation?</h3>
  • Take Milk of Magnesia once day, preferably before bed, in divided doses, or as prescribed by a physician.
  • suggested dosage: 30 mL to 60 mL for adults and kids 12 years of age and older. 15 mL to 30 mL for children aged 6 to 11 years.

learn more about milk of magnesia here

brainly.com/question/15178597

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the question you are looking for is

People often take milk of magnesia to reduce the discomfort associated with acid stomach or heartburn. The recommended dose is 1 teaspoon, which contains 4.00x 10^{2} mg of Mg(OH)_2. What volume of an HCl solution with a pH of 1.3 can be neutralized by one dose of milk of magnesia? If the stomach contains 2.00x10^{2}mL of pH 1.3 solution, is all the acid neutralized? If not, what fraction is neutralized?

7 0
1 year ago
Why does a 4 carbon linear alkane, butane c4h10, have two more hydrogens ?
Scilla [17]
Alkanes are hydrocarbons that only contain single bonds in them. A carbon can bond with up to 4 atoms, even with another carbon atom. So, in a C-C bond, 3 more H atoms can bond to each of the C atom. Generally, the chemical formula for alkanes is CₓH₂ₓ₊₂. So for butane, there are 4 C atoms. The corresponding H atoms are 2(4) + 2 = 10. That's why it's chemical formula is C₄H₁₀.
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In an experiment, you use a ruler to measure two plants. What can you do with the data you gather?
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C. is the best choice
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Read 2 more answers
An analytical chemist weighs out 0.055g of an unknown triprotic acid into a 250mL volumetric flask and dilutes to the mark with
Katarina [22]

Answer:

Mass of the unknown acid is 4.0g

Explanation:

The determine the molar mass of the unknown acid, the steps below can be followed

Firstly, determine the concentration of the acid, the formula below can be used;

ConcA × Va/ConcB × Vb = Na/Nb

Where ConcA is the concentration of the unknown acid

ConcB is the concentration of the NaOH base

Va is the volume of acid and Vb is the volume of base

Since, the titration was said to have reached an equivalent point, it means the number of moles of the acid (Na) was equal to the number of moles of the base (Nb) and thus both will be assumed to be 1

Thus

ConcA × 250/0.13 × 6.6 = 1/1

ConcA = 0.13 × 6.6/250

ConcA = 0.003432M

Then, determine the actual number of moles (n) of the unknown acid used,

ConcA = no of moles of acid/volume of acid (in dm³ or L)

To convert mL to L, we divide by 1000

Hence, 250ml = 0.25L

0.003432 = n/0.25

n = 0.003432 × 0.25

n = 0.01373 moles

To determine the molar mass;

n = mass/molar mass

The mass was given in the question to be 0.055g

Thus

0.01373 = 0.055/molar mass

molar mass = 0.055/0.01373

molar mass = 4.0g

5 0
2 years ago
Which temperatures originally represented the fixed points<br> Celsius temperature scale?
frez [133]

Answer:Since 1743 the Celsius scale has been based on 0 °C for the freezing point of water and 100 °C for the boiling point of water at 1 atm pressure. Prior to 1743 the values were reversed (i.e. the boiling point was 0 degrees and the freezing point was 100 degrees).

Explanation: i no it

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