Answer:
K₂CO₃
Explanation:
Given parameters:
Number of moles of K = 0.104mol
Number of moles of C = 0.052mol
Number of moles of O = 0.156mol
Method
From the given parameters, to calculate the empirical formula of the elements K, C and O, we reduce the given moles to the simplest fraction.
Empirical formula is the simplest formula of a compound and it differs from the molecular formula which is the actual formula of a compound.
- Divide the given moles through by the smallest which is C, 0.052mol.
- Then approximate values obtained to the nearest whole number of multiply by a factor to give a whole number ratio.
- This is the empirical formula
Solution
Elements K C O
Number of moles 0.104 0.052 0.156
Dividing by the
smallest 0.104/0.052 0.052/0.052 0.156/0.052
2 1 3
The empirical formula is K₂CO₃
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Answer:
Thus, first conversion of mass of methane into moles by dividing it with 16.04 g/mol
Mass = 138.63 g
Explanation:
The balanced chemical reaction is shown below:-
Firstly the moles of methane gas reacted must be calculate as:-
Given, mass of methane = 50.6 g
Molar mass of methane gas = 16.04 g/mol
The formula for the calculation of moles is:-
Thus, from the reaction stoichiometry,
1 mole of methane produces 1 mole of carbon dioxide
Also,
3.15 mole of methane produces 3.15 mole of carbon dioxide
Moles of 
= 3.15 mole
Molar mass of = 44.01 g/mol
Mass = Moles*Molar mass = 
g = 138.63 g
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