1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svet_ta [14]
3 years ago
9

Please help.. match the letter with the statements below?!

Chemistry
2 answers:
FinnZ [79.3K]3 years ago
7 0
1 B
2 D
3 E
4 A
5 C

There
pashok25 [27]3 years ago
3 0
1. Experimental Variable, B
2. Controlled conditions, D
3. Experimental group, E
4. Controlled group, A
5. Data, C

You might be interested in
For the reaction represented by the equation AgNO3 + NaCl ® NaNO3 + AgCl,
sergeinik [125]

Answer:

7

Explanation:

7 mol AgCL * \frac{1 mol AgNO3}{1 mol AgCl}

You can cancel out the "mol AgCl" to get 7 moles of AgNO3

6 0
2 years ago
What happens to cause a female to begin puberty
vova2212 [387]
Hormones which are chemical produced in the body.The hormones are like chemical messages which send a message to the ovaries.the ovaries release hormones which work together hence starting puberty
5 0
4 years ago
A compound with molecular formula C6H15N exhibits a singlet at d 0.9 (1H), a triplet at d 1.10 (3H), a singlet at d1.15 (9H), an
LuckyWell [14K]

Answer:

N-ethyl-2-methylpropan-2-amine

Explanation:

 

In this case, we have to start with the <u>IR info</u>. The signal on 3400 cm^-1 indicates the presence of a <u>hydrogen bonded to the heteroatom</u>. In this case, we have nitrogen in the formula, so we will have the <u>amine group</u>.

On the other hand, we have to analyze the NMR info:

a)  We have 2 singlets => This indicates the presence of 2 different hydrogens without neighbors.

b) We have a triplet => This indicates the presence of <u>CH3 bonded to a CH2</u>.

c) We have a quartet => This indicates the presence of <u>CH2 bonded to a CH3</u>.

From b) and c) we can conclude that we have the <u>ethyl group</u> bonded to a nitrogen.  

Finally, we have to add 4 more carbons in such a way that we only have a single signal. In this case the <u>ter-butyl group</u>.

In that way, we will have <u>2 singlets</u> (from the CH3 groups in the ter-butyl and the H on the N). Also, we will have the <u>quartet </u>on the CH2 in the ethyl group and the <u>triplet</u> on the CH3 in the ethyl group

6 0
3 years ago
Which quality do scientists exhibit when they invent ways to solve problems and produce new things?
serious [3.7K]
Creativity is your best option here !
7 0
3 years ago
Read 2 more answers
9. A student is dissolving sugar in water. What can
pychu [463]

Answer:

D

Explanation:

Sugar will dissolve faster when you stir the solution quickly because the act of stirring increases kinetic energy which increases the temperature.

4 0
3 years ago
Read 2 more answers
Other questions:
  • Which of these elements is unlikely to form covalent bonds? s, h, mg, ar, si?
    6·2 answers
  • Identify the functional groups attached to the benzene ring as either, being electron withdrawing, electron donating, or neither
    5·1 answer
  • Deforestation typically
    6·1 answer
  • Magnesium burns with a very bright light. When the flame goes out, a White powder is left behind. What is the name of that white
    13·2 answers
  • Which is TRUE of the reactants in this displacement reaction? Fe + 2HCl FeCl2 + H2
    5·2 answers
  • Which statement about oxidation and reduction in a voltaic cell is true? A. Both oxidation and reduction occur at the anode. B.
    9·1 answer
  • If 4.04g of h2 gas react with oxygen gas to create 36.36g of water, how many grams of oxygen reacted?
    11·1 answer
  • What is an atomic number? An atomic mass?
    8·2 answers
  • Describe how you could show by adding aqueous sodium hydroxide and aqueous ammonia that a solution contained zinc ions.
    14·1 answer
  • Uranium and radium are found in many rocky soils throughout the world. Both undergo radioactive decay, and one of the products i
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!