For 1. 00 l of an aqueous buffer containing 60. 0 mmol of acetic acid (pa=4. 76) and 40. 0 mmol of acetate, the pH of this buffer is 4.58.
<h3>What is handerson Hasselbalch equation? </h3>
It is expressed as:
pH = pKa + log [A-]/[HA]
where,
[A-] is the molar concentration of conjugate base
[HA] is the molar concentration of weak acid
Given,
pKa = 4.76
<h3>Calculation of concentration:</h3>
C = n/V
= 60/1000
= 0.06M
C = 40/1000
= 0.04M
Now, substituting values in equation we get,
pH = 4.76 + log(0.04/0.06)
pH = 4.76 + (-0.176)
pH = 4.58
Thus by using Henderson Hasselbalch equation we find the value of pH of the buffer is 4.58.
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7 protons means that N atom has 7 electrons
1st level can have only 2 e⁻, and we have left over of 7-2=5 e⁻, that will go on the second level.
B. 2,5
What is the options but i would say A but not sure
pH scale is used to measure the acidity or alkalinity on a scale of 0-14 where 0-6.9 is the acidic region , 7.1-14 is the basic region and 7 is for the neutral substance. We can calculate the concentration of proton from pH.
![pH=-log[H^+]](https://tex.z-dn.net/?f=pH%3D-log%5BH%5E%2B%5D)
where ![[H^+]](https://tex.z-dn.net/?f=%5BH%5E%2B%5D)
is the concentration of proton
As per the question ,the pH of coffee is 5.6 and we need to find the concentration of proton so putting the values in the above equation, we get
![5.6=-log[H^+]](https://tex.z-dn.net/?f=5.6%3D-log%5BH%5E%2B%5D)
![-5.6=log[H^+]](https://tex.z-dn.net/?f=-5.6%3Dlog%5BH%5E%2B%5D)
![antilog(-5.6)= [H^+]](https://tex.z-dn.net/?f=antilog%28-5.6%29%3D%20%5BH%5E%2B%5D)
![[H^+]= 2.511\times10^-^6 M](https://tex.z-dn.net/?f=%5BH%5E%2B%5D%3D%202.511%5Ctimes10%5E-%5E6%20M)
